1 #include <bits/stdc++.h>
2 #define pb push_back
3 #define _for(i,a,b) for(int i = (a);i < (b);i ++)
4 #define INF 1000000003
5 #define ll long long
6
7 using namespace std;
8
9 const int maxn = 50003;
10 inline ll read()
11 {
12 ll ans = 0;
13 char ch = getchar(), last = ' ';
14 while(!isdigit(ch)) last = ch, ch = getchar();
15 while(isdigit(ch)) ans = (ans << 1) + (ans << 3) + ch - '0', ch = getchar();
16 if(last == '-') ans = -ans;
17 return ans;
18 }
19 inline void write(ll x)
20 {
21 if(x < 0) x = -x, putchar('-');
22 if(x >= 10) write(x / 10);
23 putchar(x % 10 + '0');
24 }
25 struct edge
26 {
27 ll to;
28 ll cost;
29 };
30 vector<edge> G[maxn];
31
32 ll V,E,B;
33
34 typedef pair<ll,ll> P;//first 是最短距离,second 是顶点编号
35 ll d[maxn];
36 ll f[maxn];
37
38 bool shortest_path(ll s,ll lim)
39 {
40 priority_queue<P,vector<P>,greater<P>> que;
41 ll ans = -1;
42 _for(i,1,V+1)
43 d[i] = INF;
44 d[s] = 0;
45 que.push(P{0,s});
46
47 while(!que.empty())
48 {
49 P p = que.top();que.pop();
50 ll v = p.second;
51 if(d[v] < p.first) continue;
52 _for(i,0,G[v].size())
53 {
54 edge e = G[v][i];
55 if(d[e.to] > d[v] + e.cost && f[e.to] <= lim)
56 {
57 d[e.to] = d[v] + e.cost;
58 que.push(P{d[e.to],e.to});
59 }
60 }
61 }
62 if(d[V]>=B)
63 return false;
64 return true;
65 }
66 bool C(ll dd)
67 {
68 return shortest_path(1,dd);
69 }
70 void solve()
71 {
72 ll t[maxn];
73 memcpy(t,f,maxn*sizeof(ll));
74 sort(t+1,t+V+1);
75 ll lb = 1,ub = V;
76
77 if(!C(t[ub]))
78 {
79 printf("AFK\n");
80 return ;
81 }
82 while(ub - lb > 1)
83 {
84 int mid = lb+(ub-lb)/2;
85 if(C(t[mid])) ub = mid;
86 else lb = mid;
87 }
88 if(C(t[lb]))
89 write(t[lb]);
90 else
91 write(t[ub]);
92 }
93 int main()
94 {
95 // freopen("testdata (1).in","r+",stdin);
96
97 V = read(),E = read(),B = read();
98 _for(i,1,V+1)
99 { f[i] = read();}
100 // scanf("%d %d %d",&V,&E,&st);
101 _for(i,0,E)
102 {
103 ll s,t,c;
104 s = read(),t = read(),c = read();
105 // scanf("%d %d %d",&s,&t,&c);
106 G[s].push_back(edge{t,c});
107 G[t].push_back(edge{s,c});
108
109 }
110
111 solve();
112
113 //printf("%d ",d[i]);
114 return 0;
115 }