P1156-垃圾陷阱 

 1 #include <bits/stdc++.h>
 2 #define _for(i,a,b) for(int i = (a);i < b;i ++)
 3 #define _rep(i,a,b) for(int i = (a);i > b;i --)
 4 #define INF 0x3f3f3f3f
 5 #define MOD 1000000007
 6 typedef long long ll;
 7 using namespace std;
 8 inline ll read()
 9 {
10     ll ans = 0;
11     char ch = getchar(), last = ' ';
12     while(!isdigit(ch)) last = ch, ch = getchar();
13     while(isdigit(ch)) ans = (ans << 1) + (ans << 3) + ch - '0', ch = getchar();
14     if(last == '-') ans = -ans;
15     return ans;
16 }
17 inline void write(ll x)
18 {
19     if(x < 0) x = -x, putchar('-');
20     if(x >= 10) write(x / 10);
21     putchar(x % 10 + '0');
22 }
23 struct rubbish
24 {
25     int t;
26     int f;
27     int h;
28     bool operator < (rubbish b)
29     {
30         return t < b.t;
31     }
32 };
33 int D,G;
34 rubbish a[103];
35 int dp[103][103];
36 int main()
37 {
38     D = read(), G = read();
39     
40     dp[0][0] = 10;
41     _for(i,1,G+1)
42         a[i].t = read(),a[i].f = read(),a[i].h = read();
43     sort(a+1,a+G+1);
44     _for(i,0,G)
45         _for(j,0,D)
46         {
47             if(dp[i][j]>=a[i+1].t)
48             {
49                 int sm = j+a[i+1].h;
50                 if(sm >= D)
51                 {
52                     write(a[i+1].t);
53                     return 0;
54                 }
55                 dp[i+1][j] = max(dp[i+1][j],dp[i][j]+a[i+1].f);
56                 dp[i+1][sm] = max(dp[i+1][sm],dp[i][j]);
57             }
58         }
59     int rnt = INT_MIN;
60     _for(i,1,G+1)
61         rnt = max(rnt,dp[i][0]);
62     write(rnt);
63     return 0;
64 }

 

posted @ 2019-08-26 13:18  Asurudo  阅读(248)  评论(0)    收藏  举报