题目链接
混合图+欧拉回路+最大流
1,双向边也只能走一次。
2,不需要判断是否连通
Kuangbin博客
#include <iostream>
#include <cstdio>
#include <cstring>
#include <map>
#include <vector>
#include <cmath>
#include <algorithm>
#include <queue>
#include <stack>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
const int Maxn = 200+10;
const int INF = 0x3f3f3f3f;
const long long LINF = 1e18;
struct Edge {
int v, cap, flow, next;
} edge[Maxn*Maxn*2];
int h[Maxn], edge_cnt;
int indx[Maxn], deep[Maxn], qu[Maxn];
int out[Maxn], in[Maxn], D[Maxn];
void add(int u, int v, int c) {
edge[edge_cnt].v = v;
edge[edge_cnt].cap = c;
edge[edge_cnt].flow = 0;
edge[edge_cnt].next = h[u];
h[u] = edge_cnt++;
edge[edge_cnt].v = u;
edge[edge_cnt].cap = 0;
edge[edge_cnt].flow = 0;
edge[edge_cnt].next = h[v];
h[v] = edge_cnt++;
}
bool bfs(int s, int t) {
int head = 0, tail = 0;
memset(deep, 0, sizeof(deep));
deep[s] = 1; qu[tail++] = s;
while(head < tail) {
int u = qu[head++];
for(int i = h[u]; i != -2; i = edge[i].next) {
Edge &e = edge[i];
if(deep[e.v] == 0 && e.cap-e.flow > 0) {
deep[e.v] = deep[u]+1;
qu[tail++] = e.v;
}
}
}
if(deep[t] > 0) return true;
else return false;
}
int dfs(int cur, int t, int a) {
if(cur == t || a == 0) return a;
int flow = 0, f;
if(indx[cur] == -1) indx[cur] = h[cur];
for(int &i = indx[cur]; i != -2; i = edge[i].next) {
Edge &e = edge[i];
if(deep[e.v] == deep[cur]+1) {
f = dfs(e.v, t, min(a, e.cap-e.flow));
if(f > 0) {
e.flow += f;
edge[i^1].flow -= f;
flow += f;
a -= f;
if(a == 0) break;
}
}
}
return flow;
}
void dinic(int s, int t) {
int ans = 0;
while(bfs(s, t)) {
memset(indx, -1, sizeof(indx));
ans += dfs(s, t, INF);
}
return;
}
int main(void)
{
int T;
scanf("%d", &T);
while(T--) {
int N, M, u, v, c;
scanf("%d%d", &N, &M);
memset(out, 0, sizeof(out));
memset(in, 0, sizeof(in));
for(int i = 0; i < Maxn; ++i) h[i] = -2;
edge_cnt = 0;
for(int i = 0; i < M; ++i) {
scanf("%d%d%d", &u, &v, &c);
in[v]++; out[u]++;
if(c == 1) add(u, v, 0);
else add(u, v, 1);
}
bool ok = true;
for(int i = 1; i <= N; ++i) {
D[i] = in[i]-out[i];
if(abs(D[i])%2 == 1) {
ok = false; break;
}
if(D[i] < 0) {
add(0, i, -D[i]/2);
}
if(D[i] > 0) {
add(i, N+1, D[i]/2);
}
}
if(ok) {
dinic(0, N+1);
for(int i = h[0]; i != -2; i = edge[i].next) {
if(edge[i].flow != edge[i].cap) {
ok = false; break;
}
}
}
if(ok) printf("possible\n");
else printf("impossible\n");
}
return 0;
}