php 中英文混编并且中文是十六进制 unicode 的字符串的解码方案

到网上找到一段十进制unicode串的解码方案，我发挥了下，把十六进制的解码也给解决了：

英文和十六进制中文混编的：

 

function conv($str)
    {
        preg_match_all("/\\\\u.{4}|.+/U",$str,$r);
                $ar = $r[0]; 
                foreach($ar as $k=>$v)
                { 
                    if(substr($v,0,2) == "\\u")                
                        $ar[$k] = iconv("UCS-2","utf-8",pack("H4",substr($v,-4)));                         
                }
                return join("",$ar); 
        //return iconv("UCS-2","utf-8",pack("H4",$str));
    } 

 

 

 

网上的：

<?php
        /* 
        方法作用 ：对应JS中的escape函数,即将字符串转换成%+十六进制数                
        */
        function phpEscape($str) 
        { 
                $sublen=strlen($str); 
                $retrunString=""; 
                for ($i=0;$i<$sublen;$i++) 
                { 
                        if(ord($str[$i])>=127) 
                        { 
                                $tmpString=bin2hex(iconv("utf-8","ucs-2",substr($str,$i,2))); 
                                //$tmpString=substr($tmpString,2,2).substr($tmpString,0,2); //window下可能要打开此项 
                                $retrunString.="%u".$tmpString; 
                                $i++; 
                        } else { 
                                $retrunString.="%".dechex(ord($str[$i])); 
                        } 
                } 
                return $retrunString; 
        }

        /* 
        方法作用 ：对应JS中的unescape函数,%+十六进制数转换成中文字符                      
        */
        function phpUnescape($str)
        { 
                $str = rawurldecode($str); 
                
                preg_match_all("/%u.{4}|&#x.{4};|&#d+;|.+/U",$str,$r);
                $ar = $r[0]; 
                foreach($ar as $k=>$v)
                { 
                        if(substr($v,0,2) == "%u")                $ar[$k] = iconv("UCS-2","utf-8",pack("H4",substr($v,-4))); 
                        elseif(substr($v,0,3) == "&#x")        $ar[$k] = iconv("UCS-2","utf-8",pack("H4",substr($v,3,-1))); 
                        elseif(substr($v,0,2) == "&#")        $ar[$k] = iconv("UCS-2","utf-8",pack("n",substr($v,2,-1)));
                }
                return join("",$ar); 
        }
?>