摘要: Greedy approach: function LIS(nums) { if (nums.length 0) return []; // 先取得第一项 const results = [[nums[0]]]; for (let i = 1; i < nums.length; i++) { con 阅读全文
posted @ 2025-06-10 13:42 Zhentiw 阅读(13) 评论(0) 推荐(0)