如何修改新PostgreSQLJSON数据类型中的字段?

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https://cloud.tencent.com/developer/ask/50349

如何修改新PostgreSQLJSON数据类型中的字段?

 
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使用PostgreSQL 9.3,我可以选择JSON数据类型的特定字段,但是如何使用UPDATE修改它们呢?我在PostgreSQL文档中或在线的任何地方都找不到这方面的任何例子。我尝试过显而易见的:

postgres=# create table test (data json);
CREATE TABLE
postgres=# insert into test (data) values ('{"a":1,"b":2}');
INSERT 0 1
postgres=# select data->'a' from test where data->>'b' = '2';
 ?column?
----------
 1
(1 row)
postgres=# update test set data->'a' = to_json(5) where data->>'b' = '2';
ERROR:  syntax error at or near "->"
LINE 1: update test set data->'a' = to_json(5) where data->>'b' = '2...
提问于 2018-02-262018-02-26 08:00:20

如何修改新PostgreSQLJSON数据类型中的字段?

2 个回答

用户回答回答于 2018-02-262018-02-26 16:33:55

合并2个(或更多)JSON对象(或连接数组):

SELECT jsonb '{"a":1}' || jsonb '{"b":2}', -- will yield jsonb '{"a":1,"b":2}'
       jsonb '["a",1]' || jsonb '["b",2]'  -- will yield jsonb '["a",1,"b",2]'

所以,设置一个简单的键可以使用:

SELECT jsonb '{"a":1}' || jsonb_build_object('<key>', '<value>')

何地<key>应该是字符串,而且<value>可以是任何类型的to_jsonb()接受。

为在JSON层次结构中深层设置一个值,jsonb_set()功能可用于:

SELECT jsonb_set('{"a":[null,{"b":[]}]}', '{a,1,b,0}', jsonb '{"c":3}')
-- will yield jsonb '{"a":[null,{"b":[{"c":3}]}]}'

全参数列表jsonb_set():

jsonb_set(target         jsonb,
          path           text[],
          new_value      jsonb,
          create_missing boolean default true)

path也可以包含JSON数组索引&出现在那里的负整数从JSON数组的末尾开始计数。但是,一个不存在但正的JSON数组索引将将元素追加到数组的末尾:

SELECT jsonb_set('{"a":[null,{"b":[1,2]}]}', '{a,1,b,1000}', jsonb '3', true)
-- will yield jsonb '{"a":[null,{"b":[1,2,3]}]}'

为插入JSON数组(同时保留所有原始值),jsonb_insert()函数可以使用:

SELECT jsonb_insert('{"a":[null,{"b":[1]}]}', '{a,1,b,0}', jsonb '2')
-- will yield jsonb '{"a":[null,{"b":[2,1]}]}', and
SELECT jsonb_insert('{"a":[null,{"b":[1]}]}', '{a,1,b,0}', jsonb '2', true)
-- will yield jsonb '{"a":[null,{"b":[1,2]}]}'

全参数列表jsonb_insert():

jsonb_insert(target       jsonb,
             path         text[],
             new_value    jsonb,
             insert_after boolean default false)

中出现的.path从JSON数组的末尾计数。

因此,将f.exe.追加到JSON数组的末尾可以通过以下方式完成:

SELECT jsonb_insert('{"a":[null,{"b":[1,2]}]}', '{a,1,b,-1}', jsonb '3', true)
-- will yield jsonb '{"a":[null,{"b":[1,2,3]}]}', and

但是,此功能的工作方式略有不同(与jsonb_set())当pathtarget是JSON对象的密钥。在这种情况下,它只会在不使用密钥时为JSON对象添加一个新的键值对。如果使用它,它将引发一个错误:

SELECT jsonb_insert('{"a":[null,{"b":[1]}]}', '{a,1,c}', jsonb '[2]')
-- will yield jsonb '{"a":[null,{"b":[1],"c":[2]}]}', but
SELECT jsonb_insert('{"a":[null,{"b":[1]}]}', '{a,1,b}', jsonb '[2]')
-- will raise SQLSTATE 22023 (invalid_parameter_value): cannot replace existing key

删除键(或索引)从JSON对象(或者,从数组)执行-操作员:

SELECT jsonb '{"a":1,"b":2}' - 'a', -- will yield jsonb '{"b":2}'
       jsonb '["a",1,"b",2]' - 1    -- will yield jsonb '["a","b",2]'

从JSON层次结构的深处删除可以用#-

SELECT '{"a":[null,{"b":[3.14]}]}' #- '{a,1,b,0}'
-- will yield jsonb '{"a":[null,{"b":[]}]}'

但可以使用以下方法直接聚合到json对象中,而不是聚合JSON字符串json_object_agg().

CREATE OR REPLACE FUNCTION "json_object_set_key"(
  "json"          json,
  "key_to_set"    TEXT,
  "value_to_set"  anyelement
)
  RETURNS json
  LANGUAGE sql
  IMMUTABLE
  STRICT
AS $function$
SELECT concat('{', string_agg(to_json("key") || ':' || "value", ','), '}')::json
  FROM (SELECT *
          FROM json_each("json")
         WHERE "key" <> "key_to_set"
         UNION ALL
        SELECT "key_to_set", to_json("value_to_set")) AS "fields"
$function$;

SQLFiddle

一个版本,它设置多个键和值:

CREATE OR REPLACE FUNCTION "json_object_set_keys"(
  "json"          json,
  "keys_to_set"   TEXT[],
  "values_to_set" anyarray
)
  RETURNS json
  LANGUAGE sql
  IMMUTABLE
  STRICT
AS $function$
SELECT concat('{', string_agg(to_json("key") || ':' || "value", ','), '}')::json
  FROM (SELECT *
          FROM json_each("json")
         WHERE "key" <> ALL ("keys_to_set")
         UNION ALL
        SELECT DISTINCT ON ("keys_to_set"["index"])
               "keys_to_set"["index"],
               CASE
                 WHEN "values_to_set"["index"] IS NULL THEN 'null'::json
                 ELSE to_json("values_to_set"["index"])
               END
          FROM generate_subscripts("keys_to_set", 1) AS "keys"("index")
          JOIN generate_subscripts("values_to_set", 1) AS "values"("index")
         USING ("index")) AS "fields"
$function$;
CREATE OR REPLACE FUNCTION "json_object_update_key"(
  "json"          json,
  "key_to_set"    TEXT,
  "value_to_set"  anyelement
)
  RETURNS json
  LANGUAGE sql
  IMMUTABLE
  STRICT
AS $function$
SELECT CASE
  WHEN ("json" -> "key_to_set") IS NULL THEN "json"
  ELSE (SELECT concat('{', string_agg(to_json("key") || ':' || "value", ','), '}')
          FROM (SELECT *
                  FROM json_each("json")
                 WHERE "key" <> "key_to_set"
                 UNION ALL
                SELECT "key_to_set", to_json("value_to_set")) AS "fields")::json
END
$function$;
CREATE OR REPLACE FUNCTION "json_object_set_path"(
  "json"          json,
  "key_path"      TEXT[],
  "value_to_set"  anyelement
)
  RETURNS json
  LANGUAGE sql
  IMMUTABLE
  STRICT
AS $function$
SELECT CASE COALESCE(array_length("key_path", 1), 0)
         WHEN 0 THEN to_json("value_to_set")
         WHEN 1 THEN "json_object_set_key"("json", "key_path"[l], "value_to_set")
         ELSE "json_object_set_key"(
           "json",
           "key_path"[l],
           "json_object_set_path"(
             COALESCE(NULLIF(("json" -> "key_path"[l])::text, 'null'), '{}')::json,
             "key_path"[l+1:u],
             "value_to_set"
           )
         )
       END
  FROM array_lower("key_path", 1) l,
       array_upper("key_path", 1) u
$function$;
 
用户回答回答于 2018-02-262018-02-26 17:03:04

 

UPDATE objects
SET body = jsonb_set(body, '{name}', '"Mary"', true)
WHERE id = 1; 

其中主体是jsonb列类型。

posted on 2018-08-09 17:59  傻瓜乐园  阅读(2774)  评论(0)    收藏  举报

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