JS截取URL参数 

<html>
<head>
<meta charset="utf-8">
<title>截取url参数</title>
<script type="text/javascript">
    /**
     * getParamVal 基础函数
     * 获取url中参数的key和value
     * 返回json对象
     */
    function getParamVal() {
        var params = {};

        if ( location.search !== '' ) {
            var arr = location.search.substring(1).split('&');

            for ( var i = 0, iLen = arr.length; i < iLen; i ++ ) {
                var aTmp = arr[i].split('='), value = decodeURIComponent(aTmp[1]), numberVal = Number(value);
                //处理数字
                if ( typeof numberVal === 'number' && numberVal === numberVal ) {
                    value = numberVal;
                }
                //处理布尔值
                if ( value === 'true' || value === 'false' ) {
                    value = value === 'true';
                }
                params[aTmp[0]] = value;
            }
        }
        return params;
    }
    
    //用法：url html?id=5&state=5asdfasede&viral=2
    /*
    var params = getParamVal();
    alert(params['id']);
    */


    /**
     * 智能截取url参数中的数值
     * getParamNumber 获取参数值中从第n位开始截取len长度的数字，当遇到非数字类型时终止截取
     * 注：依赖 getParamVal 函数
     * 返回截取后的数值，number类型
     */
    function getParamNumber(key, n, len) {
        var vals = getParamVal()[key],
            valN = '';

        if ( !vals ) return undefined;
        for ( var i = n; i < len+n; i ++ ) {
            var iTmp = Number(vals.charAt(i));
            if (typeof iTmp == 'number' && iTmp === iTmp) {
                valN += vals.charAt(i);
            } else {
                break;
            }
        }
        return valN ? Number(valN) : undefined;
    }

    //用法 url html?state=210.0&openid=520SN6jhUe5gI&id=15524ses
    alert( getParamNumber('openid', 1, 3) );

</script>
</head>
<body>

</body>
</html>

 

posted @ 2018-12-20 15:47  _yuelang  阅读(3998)  评论(0)    收藏  举报