HDOJ 1039 Easier Done Than Said? 简单的字符串处理
摘要:#include"stdio.h"
#include"string.h" int vo(char *psw,int i)
{return (psw[i]=='a'||psw[i]=='e'||psw[i]=='i'||psw[i]=='o'||psw[i]=='u');}
int main()
{ char psw[21],ans[2][15]={{"not acceptable"},{"acceptable"}}; while(get
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posted @ 2012-02-28 00:55
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