实验二
任务一:
源代码:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define N 100
#define CNT 5
int main() {
int number;
int i;
srand(time(0)); // 以当前系统时间作为随机种子
for(i = 0; i < CNT; ++i) {
number = rand() % 100 + 1;
printf("20490042%04d\n", number);
}
return 0;
}
运行结果:

回答问题:
问题1:程序的功能是随机生成5个学员编号
问题2:line14的功能是取随机数的个位和十位,加到204900420000后面,再赋值给number,作为最终编号
问题3:用0补齐随机生成的学号,使学号20490042后保持有四位数
问题4:使每次生成的学号随机,删去后每次生成的结果相同
任务二:
源代码:
#include <stdio.h>
int main() {
int choice, quantity;
float total_price = 0, amount_paid, change;
while (1) {
printf("\n自动饮料售卖机菜单:\n");
printf("1. 可乐 - 3 元/瓶\n");
printf("2. 雪碧 - 3 元/瓶\n");
printf("3. 橙汁 - 5 元/瓶\n");
printf("4. 矿泉水 - 2 元/瓶\n");
printf("0. 退出购买流程\n");
printf("请输入饮料编号: ");
scanf("%d", &choice);
if (choice == 0)
break;
if (choice < 1 || choice > 4) {
printf("无效的饮料编号,请重新输入。\n");
continue;
}
printf("请输入购买的数量: ");
scanf("%d", &quantity);
if (quantity < 0) {
printf("购买数量不能为负数,请重新输入。\n");
continue;
}
if(choice == 1 || choice == 2)
total_price += 3 * quantity;
else if(choice == 3)
total_price += 5 * quantity;
else
total_price += 2 * quantity;
printf("请投入金额: ");
scanf("%f", &amount_paid);
change = amount_paid - total_price;
printf("本次购买总价: %.2f 元\n", total_price);
printf("找零: %.2f 元\n", change);
total_price = 0;
}
printf("感谢您的购买,欢迎下次光临!\n");
return 0;
}
运行结果:

问题1:去掉会让每次循环的总价相加,从第二次开始,总价就会加上前一次运行的总价,而不是从0开始算
问题2:跳出本次循环,continue后的代码不再运行,直接进入下一次循环
任务3:
源代码:
#include <stdio.h>
int main() {
int i;
char light;
for (i=1;i<=4;i++){
scanf("%c",&light);
getchar();
if (light == 'r')
printf("stop!\n");
else if (light == 'g')
printf("go go go\n");
else if (light == 'y')
printf("wait a minute\n");
else
printf("something must be wrong...\n");
}
return 0;
}
运行结果:

任务4:
源代码:
#include <stdio.h>
int main() {
double n,t,min,max;
t = 0.0;
n = 0.0;
max = 0.0;
min = 20000.0;
printf("输入今日开销,直到输入-1终止\n");
while(1){
scanf("%lf",&n);
if (n == -1)
break;
else{
t += n;
if (n > max)
max = n;
if (n < min)
min = n;
}
}
printf("今日累计消费总额:%.1f\n",t);
printf("今日最高一笔开销:%.1f\n",max);
printf("今日最低一笔开销:%.1f\n",min);
return 0;
}
运行结果:

任务5:
源代码:
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
int main()
{
int a, b,c;
int i = 1;
for (i = 1;i <= 5;i++) {
scanf("%d %d %d", &a, &b, &c);
if (a + b > c && b + c > a && a + c > b) {
if (a * a + b * b == c * c || b * b + c * c == a * a || a * a + c * c == b * b)
printf("直角三角形\n");
else if (a == b && b == c)
printf("等边三角形\n");
else if (a != b && b != c && a!=c)
printf("普通三角形\n");
else
printf("等腰三角形\n");
}
else
printf("不能构成三角形\n");
}
return 0;
}
运行结果:

任务6:
源代码:
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include<stdlib.h>
#include<time.h>
int judge(int x,int n);
int main()
{
srand((unsigned)time(NULL));
int n = rand() % 30 + 1;
int guessed = 0;
printf("猜猜2026年11月哪一天是你的lucky day");
int i, x;
for (i = 1;i <= 3;i++) {
if (i == 1)
printf("开始喽,你有3次机会,猜吧(1-30):");
else
printf("再猜(1-30):");
scanf("%d", &x);
int result = judge(x, n);
if (result == 1) {
guessed = 1;
break;
}
}
if (guessed == 0)
printf("次数用光了。11月你的lucky day是%d号\n", n);
return 0;
}
int judge(int x, int n) {
if (x == n) {
printf("哇,猜中了\n");
return 1;
}
else if (x > n) {
printf("你猜的日期晚了,你的lucky day在前面哦\n");
}
else {
printf("你猜的日期早了,你的lucky day还没到呢\n");
}
return 0;
}
运行结果:



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