随笔分类 -  SQL

摘要:SELECT B.resultNo,resultList as result FROM (SELECT resultNo,(SELECT CONVERT(nvarchar, questionnaireNo)+CONVERT(nvarchar, highestQuestionNo) FROM ResultAnalyze WHERE resultNo=A.resultNo ORDER BY questionnaireNo FOR XML PATH('')) AS resultListFROM ResultAnalyze A GROUP BY resultNo) B查询代码 阅读全文
posted @ 2014-03-02 16:29 Alf7 阅读(108) 评论(0) 推荐(0)