随笔分类 - SQL
摘要:SELECT B.resultNo,resultList as result FROM (SELECT resultNo,(SELECT CONVERT(nvarchar, questionnaireNo)+CONVERT(nvarchar, highestQuestionNo) FROM ResultAnalyze WHERE resultNo=A.resultNo ORDER BY questionnaireNo FOR XML PATH('')) AS resultListFROM ResultAnalyze A GROUP BY resultNo) B查询代码
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