# - 算术运算符
print(1 + 1) # 2
n1 = 1
# n1=n1+1 # n1 += 1
# print(n1) #2
n1 += 1
# 赋值运算符: -=
print(10 - 1) # 9
# *=
print(12 * 12) # 144
print(11 / 3) # 3.666...
print(11 // 3) # 3
print(11 % 3) # 2
# 比较运算符
print(1 == 2) # False
print(1 > 2) # False
print(1 < 2) # True
print(1 >= 2) # False
print(1 <= 2) # True
# is: 比较两个变量的id是否相等
x = 10
print(id(x) == id(x)) # True
print(x is x) # True
# 逻辑运算符
# and:左右两边的条件都为True, 否则为False
print(x == 1 and x == 10) # False
print(x == 10 and x == 1) # True
# or:判断两边的条件是否成立,其1成立则为True
print(x == 10 or x == 1) # True
# not: 取反
print(x == 10) # True
print(not x == 10) # True
# no-->and-->or
# True or False
print(not x == 1 or x == 10 and x == 20) # True
# 占位符: %s
str1 = '很帅'
print('tank%s' % (str1,)) # tank很帅
str2 = '信念与我同在,我将无坚不摧!'
print('自信养成记1: %s' %(str2,))
pricel = input('请输入该用户当月扣费月租:')
all = input('请输入该用户当前余额:')
print('亲爱的移动用户,您当月月租为[%s]元,账户余额为[%s]元!'%(pricel,all))
# 链式赋值
n = 10
y = n
z = y
print(n, y, z)
n = y = z = 10
print(n, y, z)
# 交叉赋值
x = 10
y = 20
# x与y的值互换
# x =20 y = 10
z = x # 10
x = y # 20
y = z # 10
x = 10
y = 20
# 10, 20 = y=10, x=20
x, y = y, x
print(x, y) # 20 10
import time
list1 =['tank','jason']
# print('18岁的tank,是真的。')
# type
print(type(list1))
#id
print(id(list1))
# 4648825800
# 4620657608
time.sleep(5)
print('程序结束,list1被销毁')
# - 算术运算符
print(1 + 1) # 2
n1 = 1
# n1=n1+1 # n1 += 1
# print(n1) #2
n1 += 1
# 赋值运算符: -=
print(10 - 1) # 9
# *=
print(12 * 12) # 144
print(11 / 3) # 3.666...
print(11 // 3) # 3
print(11 % 3) # 2
# 比较运算符
print(1 == 2) # False
print(1 > 2) # False
print(1 < 2) # True
print(1 >= 2) # False
print(1 <= 2) # True
# is: 比较两个变量的id是否相等
x = 10
print(id(x) == id(x)) # True
print(x is x) # True
# 逻辑运算符
# and:左右两边的条件都为True, 否则为False
print(x == 1 and x == 10) # False
print(x == 10 and x == 1) # True
# or:判断两边的条件是否成立,其1成立则为True
print(x == 10 or x == 1) # True
# not: 取反
print(x == 10) # True
print(not x == 10) # True
# no-->and-->or
# True or False
print(not x == 1 or x == 10 and x == 20) # True
# 占位符: %s
str1 = '很帅'
print('tank%s' % (str1,)) # tank很帅
str2 = '信念与我同在,我将无坚不摧!'
print('自信养成记1: %s' %(str2,))
pricel = input('请输入该用户当月扣费月租:')
all = input('请输入该用户当前余额:')
print('亲爱的移动用户,您当月月租为[%s]元,账户余额为[%s]元!'%(pricel,all))
# 链式赋值
n = 10
y = n
z = y
print(n, y, z)
n = y = z = 10
print(n, y, z)
# 交叉赋值
x = 10
y = 20
# x与y的值互换
# x =20 y = 10
z = x # 10
x = y # 20
y = z # 10
x = 10
y = 20
# 10, 20 = y=10, x=20
x, y = y, x
print(x, y) # 20 10
import time
list1 =['tank','jason']
# print('18岁的tank,是真的。')
# type
print(type(list1))
#id
print(id(list1))
# 4648825800
# 4620657608
time.sleep(5)
print('程序结束,list1被销毁')
# - 算术运算符
print(1 + 1) # 2
n1 = 1
# n1=n1+1 # n1 += 1
# print(n1) #2
n1 += 1
# 赋值运算符: -=
print(10 - 1) # 9
# *=
print(12 * 12) # 144
print(11 / 3) # 3.666...
print(11 // 3) # 3
print(11 % 3) # 2
# 比较运算符
print(1 == 2) # False
print(1 > 2) # False
print(1 < 2) # True
print(1 >= 2) # False
print(1 <= 2) # True
# is: 比较两个变量的id是否相等
x = 10
print(id(x) == id(x)) # True
print(x is x) # True
# 逻辑运算符
# and:左右两边的条件都为True, 否则为False
print(x == 1 and x == 10) # False
print(x == 10 and x == 1) # True
# or:判断两边的条件是否成立,其1成立则为True
print(x == 10 or x == 1) # True
# not: 取反
print(x == 10) # True
print(not x == 10) # True
# no-->and-->or
# True or False
print(not x == 1 or x == 10 and x == 20) # True
# 占位符: %s
str1 = '很帅'
print('tank%s' % (str1,)) # tank很帅
str2 = '信念与我同在,我将无坚不摧!'
print('自信养成记1: %s' %(str2,))
pricel = input('请输入该用户当月扣费月租:')
all = input('请输入该用户当前余额:')
print('亲爱的移动用户,您当月月租为[%s]元,账户余额为[%s]元!'%(pricel,all))
# 链式赋值
n = 10
y = n
z = y
print(n, y, z)
n = y = z = 10
print(n, y, z)
# 交叉赋值
x = 10
y = 20
# x与y的值互换
# x =20 y = 10
z = x # 10
x = y # 20
y = z # 10
x = 10
y = 20
# 10, 20 = y=10, x=20
x, y = y, x
print(x, y) # 20 10
import time
list1 =['tank','jason']
# print('18岁的tank,是真的。')
# type
print(type(list1))
#id
print(id(list1))
# 4648825800
# 4620657608
time.sleep(5)
print('程序结束,list1被销毁')