11/3 <binary search>

278. First Bad Version

二分法,如果isBadVersion返回true则坏版本在左边,right = mid,否则 left = mid + 1。

注意溢出问题 left+(right - left) /2

最后return left right均可

/* The isBadVersion API is defined in the parent class VersionControl.
      boolean isBadVersion(int version); */

public class Solution extends VersionControl {
    public int firstBadVersion(int n) {
        int left = 1, right = n;
        while(left < right){
            int mid = left + (right - left) / 2;
            if(isBadVersion(mid)) right = mid;
            else left = mid + 1;
        }
        return left;
    }
}

 

posted @ 2019-11-03 11:55  阿飞哦  阅读(111)  评论(0编辑  收藏  举报