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c#选择打开本地图片,并在picturebox上显示

OpenFileDialog openfile = new OpenFileDialog();

if (openfile.ShowDialog() == DialogResult.OK && (openFileDialog1.FileName != "")
{
picturebox1.ImageLocation = openfile.FileName;
textbox.Text = openfile.FileName;
}

openfile.Dispose();

posted on 2013-08-12 17:15  点A点C  阅读(15626)  评论(0编辑  收藏  举报

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