POJ 3225 Help with Intervals 线段树 成段更新

 

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#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
const int maxn = 65666<<1;
#define lson l, m, rt<<1
#define rson m+1, r, rt<<1|1
#define mid int m = (l + r) >> 1
int col[maxn<<2], XOR[maxn<<2];
bool vis[maxn<<2];
void FXOR(int rt)
{
    if(col[rt] != -1) col[rt] ^=1;
    else XOR[rt] ^= 1; 
}
void pushdown(int rt)
{
    if(col[rt] != -1)
    {
        col[rt<<1] = col[rt<<1|1] = col[rt];
        XOR[rt<<1] = XOR[rt<<1|1] = 0;
        col[rt] = -1; 
    }
    if(XOR[rt])
    {
        FXOR(rt<<1);
        FXOR(rt<<1|1);
        XOR[rt] = 0;
    }
}

void update(char c, int L, int R, int l, int r, int rt)
{
    if(L <= l && r <= R)
    {
        if(c == 'U')
            col[rt] = 1, XOR[rt] = 0;
        else if(c == 'D')
            col[rt] = 0, XOR[rt] = 0;
        else if(c == 'C' || c == 'S')
            FXOR(rt);
        return;
    }
    pushdown(rt);
    mid;
    if(L <= m) update(c, L, R, lson);
    else if(c == 'I' || c == 'C') XOR[rt<<1] = col[rt<<1] = 0;
    if(R > m ) update(c, L, R, rson);
    else if(c == 'I' || c == 'C') XOR[rt<<1|1] = col[rt<<1|1] = 0;
}

void query(int l, int r, int rt)
{
    if(col[rt] == 1)
    {
        for(int i = l; i <= r; i++)
            vis[i] = 1;
        return;
    }
    if(l == r) return;
    pushdown(rt);
    mid;
    query(lson);
    query(rson);
}
int main()
{
    //freopen("int.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);
    int i, j;
    char l, r, c;
    int x, y;    
    col[1] = XOR[1] = 0;
    while(~scanf("%c %c%d,%d%c\n", &c, &l, &x, &y, &r))
    {
        x <<= 1; y <<= 1;
        if(l == '(')x++;
        if(r == ')')y--;
        update(c, x, y, 0, maxn-1, 1);
        
    }
    memset(vis, 0, sizeof(vis));
    query(0, maxn-1, 1);
    bool flag = 0;
    for(i = 0; i < maxn; i++)
    {
        if(vis[i])
        {
            j = i;
            while(vis[j+1]) j++;
            printf("%c%d,%d%c ", i&1 ? '(': '[', i>>1, (j+1)>>1, j&1 ? ')': ']');
            flag = 1;
            i = j;
        }
    }
    if(!flag) puts("empty set");
    return 0;
}
posted @ 2012-11-24 15:06  To be an ACMan  Views(184)  Comments(0)    收藏  举报