实验七

任务三

1屏幕上出现了按分数由高到底排序的信息

2.生成了file3.dat

3。file3.dat里面的数据信息正确，且直观可读

任务四

子任务一

1.在屏幕上正确输出了按分数由高到底排序的学生信息

2.在当前路径下生成了二进制文件file4.dat

3信息不直观可读，里面的数据是乱码

子任务二

 

#include <stdlib.h>
#define N 10

typedef struct student {
    int num;
    char name[20];
    int score;
}STU;
int main()
{
    FILE* fp;
    STU st[N];
    int i;
    i = 1;
    fp = fopen("file4.dat", "rb");
    if (fp == NULL)
    {
        printf("Failed to open XD");
        exit(0);
    }
    fread(st, sizeof(STU), N, fp);
    while(i==N)
    {
        printf("%d %s %d\n", st[i].num, st[i].name, st[i].score);
        fclose(fp);
        i++;
    }
    return 0;
}

 

 实验五

#include <stdio.h>
#include <stdio.h>
#include <string.h>
const int N = 10;
typedef struct student {
    long int id;
    char name[20];
    float objective;    
    float subjective;    
    float sum;
    char level[10];
}STU;
void input(STU s[], int n);
void output(STU s[], int n);
void process(STU s[], int n);

int main() {
    STU stu[N];

    printf("录入%d个考生信息：准考证号，姓名，客观题得分（<=40),操作题得分（<=60)\n", N);
    input(stu, N);

    printf("\n对考生信息进行处理：计算总分，确定等级\n");
    process(stu, N);

    printf("\n打印考生完整信息：准考证号，姓名，客观题得分，操作题得分，总分，等级\n");
    output(stu, N);

    return 0;
}
void input(STU s[], int n) {
    FILE* fin;
    int i;
    fin = fopen("examinee.txt", "r");
    if (!fin)
    {
        printf("fail to open examinee.txt\n");
    }

    for (i = 0; i < n; i++) {
        fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name, &s[i].objective, &s[i].subjective);
    }
    fclose(fin);
}

void output(STU s[], int n) {
    FILE* fout;
    int i;
    fout = fopen("result.txt", "w");
    if (!fout) {
        printf("fail to open result.txt\n");
    }
    for (i = 0; i < n; i++) {
        printf("%-6ld %-10s %4.2f %4.2f %4.2f %10s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
    }
    fwrite(s, sizeof(STU), n, fout);
}
void process(STU s[], int n) {
    int i, j;
    STU t;


    for (i = 0; i < n; i++)
    {
        s[i].sum = s[i].objective + s[i].subjective;
    }
    for (i = 0; i <= n - 1; i++)
    {
        for (j = i + 1; j < n; j++)
            if (s[i].sum < s[j].sum)
            {
                t = s[j];
                s[j] = s[i];
                s[i] = t;
            }

    }
    for (i = 0; i < n; i++)
    {

        if (1.0 * (i + 1) / n <= 0.1)
        {
            strcpy(s[i].level, "优秀");
        }
        else if (1.0 * (i + 1) / n <= 0.5)
        {
            strcpy(s[i].level, "合格");
        }
        else
        {
            strcpy(s[i].level, "不合格");
        }

    }

}

 

 实验总结

1.需要加强对数组运用的理解

2.需熟悉各种函数的用法

3.认真学习c语言，继续加油