实验6
实验五
task1
源代码
1 #define _CRT_SECURE_NO_WARNINGS 2 #include <stdio.h> 3 #include <string.h> 4 #define N 3 5 6 typedef struct student { 7 int id; 8 char name[20]; 9 char subject[20]; 10 double perf; 11 double mid; 12 double final; 13 double total; 14 char level[10]; 15 } STU; 16 17 void input(STU [], int); 18 void output(STU [], int); 19 void calc(STU [], int); 20 int fail(STU [], STU [], int); 21 void sort(STU [], int); 22 23 int main() { 24 STU st[N], fst[N]; 25 int k; 26 27 printf("录入学生成绩信息:\n"); 28 input(st, N); 29 30 printf("\n成绩处理...\n"); 31 calc(st, N); 32 33 k = fail(st, fst, N); 34 sort(st, N); 35 printf("\n学生成绩排名情况:\n"); 36 output(st, N); 37 38 printf("\n不及格学生信息:\n"); 39 output(fst, k); 40 41 return 0; 42 } 43 44 void input(STU s[], int n) { 45 int i; 46 47 for(i = 0; i < n; i++) 48 scanf("%d %s %s %lf %lf %lf", &s[i].id, s[i].name, s[i].subject, 49 &s[i].perf, &s[i].mid, &s[i].final); 50 } 51 52 void output(STU s[], int n) { 53 int i; 54 55 printf("-----------------\n"); 56 printf("学号 姓名 科目 平时 期中 期末 总评 等级\n"); 57 for(i = 0; i<n; i++) 58 printf("%d %-6s %-4s %-4.0f %-4.0f %-4.0f %-4.1f %s\n",s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total,s[i].level); 59 } 60 61 62 void calc(STU s[],int n) { 63 int i; 64 65 for(i = 0; i < n; i++) { 66 s[i].total = s[i].perf * 0.2 + 67 s[i].mid * 0.2 + 68 s[i].final * 0.6; 69 70 if(s[i].total >= 90) 71 strcpy(s[i].level, "优"); 72 else if(s[i].total >= 80) 73 strcpy(s[i].level, "良"); 74 else if(s[i].total >= 70) 75 strcpy(s[i].level, "中"); 76 else if(s[i].total >= 60) 77 strcpy(s[i].level, "及格"); 78 else 79 strcpy(s[i].level, "不及格"); 80 } 81 } 82 83 int fail(STU s[], STU t[], int n) { 84 int i, cnt = 0; 85 86 for(i = 0; i < n; i++) 87 if(s[i].total < 60) 88 t[cnt++] = s[i]; 89 90 return cnt; 91 } 92 93 void sort(STU s[], int n) { 94 int i, j; 95 STU t; 96 97 for(i = 0; i < n-1; i++) 98 for(j = 0; j < n-1-i; j++) 99 if(s[j].total < s[j+1].total) { 100 t = s[j]; 101 s[j] = s[j+1]; 102 s[j+1] = t; 103 } 104 }
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task2
源代码
1 #include <stdio.h> 2 #include <string.h> 3 #define N 10 4 #define M 80 5 6 typedef struct { 7 char name[M]; 8 char author[M]; 9 } Book; 10 11 int main() { 12 Book x[N] = { {"《一九八四》", "乔治.奥威尔"}, 13 {"《美丽新世界》", "赫胥黎"}, 14 {"《昨日的世界》", "斯蒂芬.茨威格"}, 15 {"《万历十五年》", "黄仁宇"}, 16 {"《一只特立独行的猪》", "王小波"}, 17 {"《百年孤独》", "马尔克斯"}, 18 {"《查令十字街84号》", "海莲.汉芙"}, 19 {"《只是孩子》", "帕蒂.史密斯"}, 20 {"《刀锋》", "毛姆"}, 21 {"《沉默的大多数》", "王小波"} }; 22 Book *ptr; 23 int i; 24 char author[M]; 25 int found; 26 27 printf("-------------------所有图书信息-------------------\n"); 28 for(ptr = x; ptr < x + N; ++ptr) 29 printf("%-30s%-30s\n", ptr->name, ptr->author); 30 31 printf("\n-------------------按作者查询图书-------------------\n"); 32 printf("输入作者名: "); 33 gets(author); 34 found = 0; 35 for(ptr = x; ptr < x + N; ++ptr) 36 if(strcmp(ptr->author, author) == 0) { 37 found = 1; 38 printf("%-30s%-30s\n", ptr->name, ptr->author); 39 } 40 41 if(!found) 42 printf("暂未收录该作者书籍!\n"); 43 44 return 0; 45 }
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task3_1
源代码
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <stdlib.h> 4 #define N 80 5 6 typedef struct FilmInfo { 7 char name[N]; 8 char director[N]; 9 char region[N]; 10 int year; 11 struct FilmInfo *next; 12 } Film; 13 14 15 void output(Film *head); 16 Film *insert(Film *head, int n); 17 18 19 int main() { 20 int n; 21 Film *head; 22 23 head = NULL; 24 printf("输入影片数目: "); 25 scanf("%d", &n); 26 27 head = insert(head, n); 28 29 printf("\n所有影片信息如下: \n"); 30 output(head); 31 32 system("pause"); 33 34 return 0; 35 } 36 37 Film *insert(Film *head, int n) { 38 int i; 39 Film *p; 40 41 for(i = 1; i <= n; ++i) { 42 p = (Film *)malloc(sizeof(Film)); 43 printf("请输入第%d部影片信息: ", i); 44 scanf("%s %s %s %d", p->name, p->director, p->region, &p->year); 45 46 p->next = head; 47 head = p; 48 } 49 50 51 return head; 52 } 53 54 void output(Film *head) { 55 Film *p; 56 57 p = head; 58 while(p != NULL) { 59 printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year); 60 p = p -> next; 61 } 62 }
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task3_2
源代码
1 #include <stdio.h> 2 #include <stdlib.h> 3 #define N 80 4 5 typedef struct FilmInfo { 6 char name[N]; 7 char director[N]; 8 char region[N]; 9 int year; 10 struct FilmInfo *next; 11 } Film; 12 13 14 void output(Film *head); 15 Film *insert(Film *head, int n); 16 17 18 int main() { 19 int n; 20 Film *head; 21 Film *p; 22 23 p = (Film *)malloc(sizeof(Film)); 24 p->next = NULL; 25 head = p; 26 27 printf("输入影片数目: "); 28 scanf("%d", &n); 29 30 head = insert(head, n); 31 32 printf("\n所有影片信息如下: \n"); 33 output(head); 34 35 36 return 0; 37 } 38 39 Film *insert(Film *head, int n) { 40 int i; 41 Film *p; 42 43 for(i = 1; i <= n; ++i) { 44 p = (Film *)malloc(sizeof(Film)); 45 printf("请输入第%d部影片信息: ", i); 46 scanf("%s %s %s %d", p->name, p->director, p->region, &p->year); 47 48 p->next = head->next; 49 head->next = p; 50 } 51 52 return head; 53 } 54 55 void output(Film *head) { 56 Film *p; 57 58 p = head->next; 59 while(p != NULL) { 60 printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year); 61 p = p -> next; 62 } 63 }
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task4
源代码
1 #include <stdio.h> 2 #include <stdlib.h> 3 #define N 10 4 5 typedef struct { 6 char isbn[20]; 7 char name[80]; 8 char author[80]; 9 double sales_price; 10 int sales_count; 11 } Book; 12 13 void output(Book x[], int n); 14 void sort(Book x[], int n); 15 double sales_amount(Book x[], int n); 16 17 int main() { 18 Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51}, 19 {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30}, 20 {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27}, 21 {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 22 {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, 23 {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42}, 24 {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}, 25 {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, 26 {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, 27 {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}}; 28 29 printf("图书销量排名(按销售册数): \n"); 30 sort(x, N); 31 output(x, N); 32 33 printf("\n图书销售总额: %.2f\n", sales_amount(x, N)); 34 35 system("pause"); 36 37 return 0; 38 } 39 40 void output(Book x[], int n){ 41 printf("%-20s %-30s %-15s %-8s %s\n","ISBN号", "书名", "作者","售价","销售册数"); 42 for(int i = 0; i < n; i++){ 43 printf("%-20s %-30s %-15s %-8.1f%d\n",x[i].isbn,x[i].name,x[i].author, 44 x[i].sales_price,x[i].sales_count); 45 } 46 } 47 48 void sort(Book x[], int n){ 49 Book temp; 50 for(int i = 0;i<n-1;i++){ 51 for(int j = 0;j<n-1-i;j++){ 52 if (x[j].sales_count < x[j+1].sales_count){ 53 temp = x[j]; 54 x[j]=x[j+1]; 55 x[j+1]=temp; 56 } 57 } 58 } 59 } 60 61 double sales_amount(Book x[], int n){ 62 double total = 0; 63 for(int i = 0;i<n;i++){ 64 total += x[i].sales_price*x[i].sales_count; 65 } 66 return total; 67 }
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task5
源代码
1 #include <stdio.h> 2 #include <stdlib.h> 3 typedef struct { 4 int year; 5 int month; 6 int day; 7 } Date; 8 9 void input(Date *pd); 10 int day_of_year(Date d); 11 int compare_dates(Date d1, Date d2); 12 13 void test1() { 14 Date d; 15 int i; 16 printf("输入日期:(以形如2025-12-19这样的形式输入)\n"); 17 for(i = 0; i < 3; ++i) { 18 input(&d); 19 printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d)); 20 } 21 } 22 23 void test2() { 24 Date Alice_birth, Bob_birth; 25 int i; 26 int ans; 27 28 printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n"); 29 for(i = 0; i < 3; ++i) { 30 input(&Alice_birth); 31 input(&Bob_birth); 32 ans = compare_dates(Alice_birth, Bob_birth); 33 34 if(ans == 0) 35 printf("Alice和Bob一样大\n\n"); 36 else if(ans == -1) 37 printf("Alice比Bob大\n\n"); 38 else 39 printf("Alice比Bob小\n\n"); 40 } 41 } 42 43 int main() { 44 printf("测试1: 输入日期, 打印输出这是一年中第多少天\n"); 45 test1(); 46 47 printf("\n测试2: 两个人年龄大小关系\n"); 48 test2(); 49 50 system("pause"); 51 } 52 53 void input(Date *pd) { 54 scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day); 55 } 56 57 int day_of_year(Date d) { 58 int month_days[12]={0,31,28,31,30,31,30,31,31,30,31,30}; 59 int total=0; 60 for(int i=1;i<d.month;i++){ 61 total += month_days[i]; 62 } 63 total += d.day; 64 int is_leap=0; 65 if((d.year % 4==0 && d.year %100 !=0) || (d.year % 400 ==0)){ 66 is_leap = 1; 67 } 68 if(is_leap && d.month > 2){ 69 total += 1; 70 } 71 return total; 72 } 73 74 int compare_dates(Date d1, Date d2) { 75 if(d1.year < d2.year) return -1; 76 if(d1.year > d2.year) return 1; 77 if(d1.month < d2.month) return -1; 78 if(d1.month > d2.month) return 1; 79 if(d1.day < d2.day) return -1; 80 if(d1.day > d2.day) return 1; 81 82 return 0; 83 }
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task6
源代码
1 #include <stdio.h> 2 #include <string.h> 3 #include <stdlib.h> 4 enum Role {admin, student, teacher}; 5 6 typedef struct { 7 char username[20]; 8 char password[20]; 9 enum Role type; 10 } Account; 11 12 void output(Account x[], int n); 13 14 int main() { 15 Account x[] = {{"A1001", "123456", student}, 16 {"A1002", "123abcdef", student}, 17 {"A1009", "xyz12121", student}, 18 {"X1009", "9213071x", admin}, 19 {"C11553", "129dfg32k", teacher}, 20 {"X3005", "921kfmg917", student}}; 21 int n; 22 n = sizeof(x)/sizeof(Account); 23 output(x, n); 24 25 system("pause"); 26 27 return 0; 28 } 29 30 void output(Account x[], int n) { 31 for(int i=0;i<n;i++) 32 { 33 printf("%-10s", x[i].username); 34 int pwd_len = strlen(x[i].password); 35 for(int j = 0; j < pwd_len; j++) 36 { 37 printf("*"); 38 } 39 printf("\t"); 40 switch(x[i].type) 41 { 42 case admin: 43 printf("admin\n"); 44 break; 45 case student: 46 printf("student\n"); 47 break; 48 case teacher: 49 printf("teacher\n"); 50 break; 51 default: 52 printf("未知角色\n"); 53 } 54 } 55 }
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task7
源代码
1 #include <stdio.h> 2 #include <string.h> 3 #include <stdlib.h> 4 typedef struct { 5 char name[20]; 6 char phone[12]; 7 int vip; 8 } Contact; 9 10 void set_vip_contact(Contact x[], int n, char name[]); 11 void output(Contact x[], int n); 12 void display(Contact x[], int n); 13 #define N 10 14 15 int main() { 16 Contact list[N] = {{"刘一", "15510846604", 0}, 17 {"陈二", "18038747351", 0}, 18 {"张三", "18853253914", 0}, 19 {"李四", "13230584477", 0}, 20 {"王五", "15547571923", 0}, 21 {"赵六", "18856659351", 0}, 22 {"周七", "17705843215", 0}, 23 {"孙八", "15552933732", 0}, 24 {"吴九", "18077702405", 0}, 25 {"郑十", "18820725036", 0}}; 26 int vip_cnt, i; 27 char name[20]; 28 29 printf("显示原始通讯录信息: \n"); 30 output(list, N); 31 32 printf("\n输入要设置的紧急联系人个数: "); 33 scanf("%d", &vip_cnt); 34 35 printf("输入%d个紧急联系人姓名:\n", vip_cnt); 36 for(i = 0; i < vip_cnt; ++i) { 37 scanf("%s", name); 38 set_vip_contact(list, N, name); 39 } 40 41 printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n"); 42 display(list, N); 43 44 system("pause"); 45 46 return 0; 47 } 48 49 void set_vip_contact(Contact x[], int n, char name[]) { 50 for(int i=0;i<n;i++){ 51 if(strcmp(x[i].name,name) == 0) 52 { 53 x[i].vip=1; 54 } 55 } 56 } 57 58 void display(Contact x[], int n) { 59 Contact temp[N]; 60 Contact buf; 61 int i,j; 62 memcpy(temp,x,sizeof(Contact)*n); 63 for(i=0;i<n-1;i++){ 64 for(j=0;j<n-1-i;j++){ 65 if(temp[j].vip<temp[j+1].vip){ 66 buf=temp[j]; 67 temp[j]=temp[j+1]; 68 temp[j+1]=buf; 69 } 70 else if(temp[j].vip==temp[j+1].vip){ 71 if(strcmp(temp[j].name,temp[j+1].name)>0){ 72 buf=temp[j]; 73 temp[j]=temp[j+1]; 74 temp[j+1]=buf; 75 } 76 } 77 } 78 } 79 output(temp,n); 80 } 81 82 void output(Contact x[], int n) { 83 int i; 84 85 for(i = 0; i < n; ++i) { 86 printf("%-10s%-15s", x[i].name, x[i].phone); 87 if(x[i].vip) 88 printf("%5s", "*"); 89 printf("\n"); 90 } 91 }
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