python响应websocket请求输出动态日志

处理线程中打开文件,每次读取一行并记录当前读取位置,没有下一行让出一秒
logfile = './logs/%s_%s.log' % (appName, time.strftime('%Y_%m_%d')) file = open(logfile, 'r', encoding='utf-8') while True: where = file.tell() line = file.readline() if not line: time.sleep(1) file.seek(where) else: send_data(conn, line.strip().encode('utf-8'))

 

posted @ 2020-12-24 18:29  1553  阅读(146)  评论(0编辑  收藏  举报