实验1

task1 代码

#include <stdio.h>
int main()
{
    printf(" O \n");
    printf("<H>\n");
    printf("I I\n");
    return 0;
}

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task2 代码

#include <stdio.h>

int main()
{
    double a, b, c;

    scanf("%lf%lf%lf", &a, &b, &c);

    if ((a+b>c) || (a+c>b) || (b+c>a) )
        printf("能构成三角形\n");
    else
        printf("不能构成三角形\n");

    return 0;
}

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task3代码

#include <stdio.h>
int main()
{
	char ans1, ans2; 

	printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有，输入n或N表示没有) :  ");
	ans1 = getchar();


	printf("\n动手敲代码实践了没? (输入y或Y表示敲了，输入n或N表示木有敲) :  ");
	ans2 = getchar();

	if (((ans1 == 'y') || (ans1 == 'Y')) && ((ans2 == 'y') || (ans2 == 'Y')))
		printf("\n罗马不是一天建成的, 继续保持哦:)\n");
	else
		printf("\n罗马不是一天毁灭的, 我们来建设吧\n");

	return 0;
}

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task4代码

#include<stdio.h>

int main()
{
    double x, y;
    char c1, c2, c3;
    int a1, a2, a3;

    scanf_s("%d %d %d", &a1, &a2, &a3);
    printf(" a1 =%d, a2 =%d, a3 =%d\n", a1, a2, a3);

    scanf_s("%c %c %c", &c1, &c2, &c3);
    printf(" c1 =%c, c2 =%c, c3 =%c\n", c1,c2,c3);

    scanf_s("%lf %lf", &x, &y);
    printf("x=%f,y=%f\n", x, y);

    return 0;

}

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task5代码

#include<stdio.h>

int main()
{
    int year;
    double seconds = 1000000000;
    double peryear = 365 * 24 * 60 * 60;
    year = seconds / peryear;
    printf("10亿秒约等于%d年\n", year);
    return 0;
}

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task6代码

1

#include <stdio.h>
#include <math.h>
int main()
{
    double x, ans;

    scanf_s("%lf", &x);
    ans = pow(x, 365);
    printf("%.2f的365次方: %.2f\n", x, ans);
    return 0;
}

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2

 #include <stdio.h>
 #include <math.h>
 int main()
 {
 double x, ans;
 while(scanf("%lf", &x) != EOF)
 {
 ans = pow(x, 365);
 printf("%.2f的365次方: %.2f\n", x, ans);
 printf("\n"); 
} 
return 0;
 }

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task7代码

#include<stdio.h>
int main()
{
    double C, F;
    while (scanf_s("%lf", &C) != EOF)
    {
        F = (9 * C) / 5 + 32;

        printf("摄氏温度为C=%.2f时，华氏度F=%.2f\n", C, F);
        printf("\n");
    }
    return 0;
}

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task8代码

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c, s, area;
    while (scanf_s("%lf %lf %lf", &a, &b, &c) != EOF)
    {
        s = (a + b + c) / 2;
        area = sqrt(s * (s - a) * (s - b) * (s - c));
        printf("a=%.0f,b=%.0f,c=%.0f, area=%.3f\n", a, b, c, area);
    }
    return 0;
}

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