winform 多线程中ShowDialog()步骤无效的解决办法
private void Form1_Load(object sender, EventArgs e) { Thread thread = new Thread(remind); thread.IsBackground = true; thread.Start(); } private void remind() { while (true) { string h = "0"; string m = "23"; if (h == DateTime.Now.Hour.ToString() && m == DateTime.Now.Minute.ToString() && DateTime.Now.Second.ToString() == "0") { Form2 form2 = new Form2(); form2.ShowDialog(); Thread.Sleep(1000); } } } form2的ShowDialog()显示并不是模式窗体,如何解决这种情况???
解决办法:
Form2 form2 = new Form2(); form2.ShowDialog(this);
作者:阿笨
【官方QQ一群:跟着阿笨一起玩NET(已满)】:422315558
【官方QQ二群:跟着阿笨一起玩C#(已满)】:574187616
【官方QQ三群:跟着阿笨一起玩ASP.NET(已满)】:967920586
【官方QQ四群:Asp.Net Core跨平台技术开发(可加入)】:829227829
【官方QQ五群:.NET Core跨平台开发技术(可加入)】:647639415
【网易云课堂】:https://study.163.com/provider/2544628/index.htm?share=2&shareId=2544628
【51CTO学院】:https://edu.51cto.com/sd/66c64
【微信公众号】:微信搜索:跟着阿笨一起玩NET

浙公网安备 33010602011771号