摘要:249. Matrixtime limit per test: 1 sec.memory limit per test: 65536 KBinput: standardoutput: standardIt is necessary to arrange numbers from 0 to 2^(N+M)-1 in the matrix with 2^N rows and 2^M columns. Moreover, numbers occupying two adjacent cells must differ only in single bit in binary notation. Ce
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摘要:SumdivTime Limit: 1000MSMemory Limit: 30000KTotal Submissions: 10515Accepted: 2477DescriptionConsider two natural numbers A and B. Let S be the sum of all natural divisors of A^B. Determine S modulo 9901 (the rest of the division of S by 9901).InputThe only line contains the two natural numbers A an
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摘要:1254.异或求和 Time Limit: 1000 MS Memory Limit: 65536 K Total Submissions: 52 (19 users) Accepted: 13 (7 users) Description给你2个区间[A,B]和[C,D],现在只要求你求出区间[A,B]和[C,D]内任意2个整数异或后的和,因为答案可能会很大,你只需将结果%mod即可。For(i:A→B) For(j:C→D) Sum += (i^j);Input输入第一行为T(T=2^(k-1) 的 x 第k位就是1这样只要求出 x某个范围 ,其它就是它的等价类了这...
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摘要:汉诺塔IXTime Limit: 3000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 404Accepted Submission(s): 235Problem Description1,2,...,n表示n个盘子.数字大盘子就大.n个盘子放在第1根柱子上.大盘不能放在小盘上. 在第1根柱子上的盘子是a[1],a[2],...,a[n]. a[1]=n,a[2]=n-1,...,a[n]=1.即a[1]是最下 面的盘子.把n个盘子移动到第3根柱子.每次只能移动1个盘子,且
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摘要:Pseudoprime numbersTime Limit: 1000MSMemory Limit: 65536KTotal Submissions: 4864Accepted: 1872DescriptionFermat's theorem states that for any prime number p and for any integer a > 1, ap = a (mod p). That is, if we raise a to the pth power and divide by p, the remainder is a. Some (but not ve
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摘要:描述求a的b次方对c取余的值输入第一行输入一个整数n表示测试数据的组数(n<100)每组测试只有一行,其中有三个正整数a,b,c(1=<a,b,c<=1000000000)输出输出a的b次方对c取余之后的结果样例输入32 3 53 100 1011 12345 12345样例输出3110481#include <iostream>#include <cstdio>using namespace std;int main(){ long long int a,b,c,t; int T; scanf("%d",&T); whil
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摘要:http://www.cnblogs.com/lonelycatcher/archive/2011/05/27/2060158.htmlGiven you n sets.All positive integers in sets are not less than 1 and not greater than m.If use these sets to combinate the new set,how many different new set you can get.The given sets can not be broken.InputThere are several case
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