字符串反码A

a = str(input("3045\n"))
for i in range(len(a)):
    if ord('a')<=ord(a[i])<=ord('z'):
        b = ord('z')-(ord(a[i])-ord('a'))
        print(chr(b),end="")
    elif ord('A')<=ord(a[i])<=ord('Z'):
        b = ord('Z')-(ord(a[i])-ord('A'))
        print(chr(b),end="")
    else:
        print(a[i],end="")

posted @ 2021-09-14 19:05  boyc  阅读(86)  评论(0)    收藏  举报