实验2 多个逻辑段的汇编源程序编写与调试
任务1-1
assume ds:data, cs:code, ss:stack data segment db 16 dup(0) data ends stack segment db 16 dup(0) stack ends code segment start: mov ax, data mov ds, ax mov ax, stack mov ss, ax mov sp, 16 mov ah, 4ch int 21h code ends end start
① 在debug中将执行到line17结束、line19之前,记录此时:寄存器(DS) = __076A__, 寄存器(SS) = _076B___, 寄存器(CS) = __076C__
② 假设程序加载后,code段的段地址是X,则,data段的段地址是_ X-2__, stack的段地址是 _ X-1___。
任务1-2
assume ds:data, cs:code, ss:stack data segment db 4 dup(0) data ends stack segment db 8 dup(0) stack ends code segment start: mov ax, data mov ds, ax mov ax, stack mov ss, ax mov sp, 8 mov ah, 4ch int 21h code ends end start
① 在debug中将执行到line17结束、line19之前,记录此时:寄存器(DS) = __076A__, 寄存器(SS) = _076B___, 寄存器(CS) = __076C__
② 假设程序加载后,code段的段地址是X,则,data段的段地址是_ X-2__, stack的段地址是 _ X-1___。
任务1-3
assume ds:data, cs:code, ss:stack data segment db 20 dup(0) ; data ends stack segment db 20 dup(0) ; stack ends code segment start: mov ax, data mov ds, ax mov ax, stack mov ss, ax mov sp, 20 ; mov ah, 4ch int 21h code ends end start
① 在debug中将执行到line17结束、line19之前,记录此时:寄存器(DS) = _076A___, 寄存器(SS) = _076C___, 寄存器(CS) = _076E___
② 假设程序加载后,code段的段地址是X,则,data段的段地址是_X-4___, stack的段地址是 _X-2___。
任务1-4
assume ds:data, cs:code, ss:stack code segment start: mov ax, data mov ds, ax mov ax, stack mov ss, ax mov sp, 20 mov ah, 4ch int 21h code ends data segment db 20 dup(0) data ends stack segment db 20 dup(0) stack ends end start
① 在debug中将执行到line9结束、line11之前,记录此时:寄存器(DS) = _076C___, 寄存器(SS) = _076E__, 寄存器(CS) = _076A___
② 假设程序加载后,code段的段地址是X,则,data段的段地址是_X+2___, stack的段地址是 _X+4___。
任务1-5
任务2
assume cs:code code segment start: mov ax, 0b800h mov ds,ax mov bx,0f00h mov cx,80 mov ax, 0403h s: mov [bx], ax inc bx inc bx loop s mov ah, 4ch int 21h code ends end start
任务3
assume cs:code data1 segment db 50, 48, 50, 50, 0, 48, 49, 0, 48, 49 ; ten numbers data1 ends data2 segment db 0, 0, 0, 0, 47, 0, 0, 47, 0, 0 ; ten numbers data2 ends data3 segment db 16 dup(0) data3 ends code segment start: ; ××× mov ax,data1 mov ds,ax ; data1 ds data2 +16B data3 +16B mov bx,0 mov dx,0 mov cx,10 s: mov dx,0 add dl,[bx] add dl,[bx+16] mov [bx+32],dl inc bx loop s mov ah, 4ch int 21h code ends end start
任务4
assume cs:code data1 segment dw 2, 0, 4, 9, 2, 0, 1, 9 ;16B data1 ends data2 segment dw 8 dup(?) data2 ends code segment start: mov ax,data1 mov ds,ax mov ax,data2 mov bx,0 mov ss,ax mov sp,16 mov cx,8 s: push [bx] add bx,2 loop s mov ah, 4ch int 21h code ends end start
任务5
assume cs:code, ds:data data segment db 'Nuist' db 2, 3, 4, 5, 6 data ends code segment start: mov ax, data mov ds, ax mov ax, 0b800H mov es, ax mov cx, 5 mov si, 0 mov di, 0f00h s: mov al, [si] and al, 0dfh mov es:[di], al mov al, [5+si] mov es:[di+1], al inc si add di, 2 loop s mov ah, 4ch int 21h code ends end start
源代码中line19的作用是? 将小写字母转化成大写字母
源代码中data段line4的字节数据的用途是? 设置字体的颜色
任务6
assume cs:code, ds:data data segment db 'Pink Floyd ' db 'JOAN Baez ' db 'NEIL Young ' db 'Joan Lennon ' data ends code segment start: mov ax, data mov ds, ax mov si, 0 mov cx, 4 s1: mov dx, cx mov bx, 0 mov cx, 4 s2: mov al, [si + bx] or al, 020h mov [si + bx], al inc bx loop s2 mov cx, dx mov ax, si add ax, 10h mov si, ax loop s1 mov ah, 4ch int 21h code ends end start
任务7
assume cs:code, ds:data, es:table data segment db '1975', '1976', '1977', '1978', '1979' dw 16, 22, 382, 1356, 2390 dw 3, 7, 9, 13, 28 data ends table segment db 5 dup( 16 dup(' ') ) ; table ends code segment start: mov ax, data mov ds, ax mov ax, table mov es, ax mov cx, 5 mov bx, 0 mov si, 0 mov di, 0 s: mov ax, ds:[bx + 2] mov es:[di + 2], ax mov ax, [bx] mov es:[di], ax mov ax, [si + 20] mov word ptr es:[di + 5], 0 mov word ptr es:[di + 7], ax mov ax, [si + 30] mov word ptr es:[di + 11], ax mov ax, es:[di + 7] div byte ptr es:[di + 11] mov es:[di + 14], al add bx, 4 add si, 2 add di, 16 loop s mov ah, 4ch int 21h code ends end start