第六周上机作业

1.定义长度位5的整型数组,输入他们的值,用冒泡排序后输出.

package yugh;

public class yu {
	
	    public static void main(String[] args) {
	           int[] arr = {3,5,9,7,1};
	           for (int i = 0; i < arr.length; i++) {
	               for (int j = 0; j < arr.length-1-i; j++) {
	               int num = 0;
	               if(arr[j] > arr[j+1]){
	                   num = arr[j];
	                   arr[j]= arr[j+1];
	                   arr[j+1] = num;
	                }
	             }
	           }
	           for (int i : arr) {
	               System.out.println(i);
	           }
	       }
	   }

  

  

2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"

package yugh;
import java.util.*;
public class he {
	    public static void main(String[] args) {
	        // TODO Auto-generated method stub
	        int []a={34,22,35,67,45,66,12,33};
	        int c=0;
	        Scanner input=new Scanner(System.in);
	        System.out.println("输入一个数");
	        int x=input.nextInt();
	        for (int i = 0; i < a.length; i++) {
	            
	            if(x==a[i]){
	                c=1;
	                System.out.println(i);
	            }
	            
	        }
	        if(c==0){
	            System.out.println("no");
	        }
	         
	    }
	}

  

  

  

3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。

package det;

public class yeah {

public static void main(String[] args) {
double[][]arr={{1,4,7,8},{2,5,8,3},{3,6,9,1},{1,2,3,4},{5,6,4,1}}; for (int i=0;i<5;i++){ for(int j=0;j<4;j++){ System.out.print(arr[i][j]); } System.out.println(); } }}

  

4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.

 

package det;

public class yeah {

    public static void main(String[] args) {

int[][]arr={{1,2,3,4},{2,3,4,5},{3,4,5,6}}; int max=0; int i,j; for(i=0;i<3;i++){ for(j=0;j<4;j++){ if(arr[i][j]>max){ max=arr[i][j]; } } } System.out.println(max);} }

  

posted on 2020-04-15 12:32  mashao  阅读(80)  评论(0编辑  收藏  举报

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