练习7-7 矩阵运算 

 1 #include<stdio.h>
 2 
 3 int main(void)
 4 {
 5     int a[10][10];
 6     int n;
 7 
 8     scanf_s("%d", &n);
 9 
10     for (int i = 0; i < n; i++)
11     {
12         for (int j = 0; j < n; j++)
13         {
14             scanf_s("%d", &a[i][j]);
15         }
16     }
17 
18     int sum = 0;
19 
20     for (int i = 0; i < n - 1; i++)
21     {
22         for (int j = 0; j < n - 1; j++)
23         {
24             if (i + j != n - 1)
25             {
26                 sum=sum+a[i][j];
27             }
28         }
29     }
30 
31     printf("%d\n", sum);
32 
33     return 0;
34 }

 

posted @ 2019-12-04 09:51  jason2018  阅读(507)  评论(0)  编辑  收藏  举报