简单C语言程序 

 1 #include<stdio.h>
 2 
 3 int main(void)
 4 {
 5     /*
 6         计算两个时间的时间差
 7     */
 8     int hour1, minute1;
 9     int hour2, minute2;
10 
11     printf("请输入第一个时间：");
12     scanf_s("%d:%d", &hour1, &minute1);
13     printf("请输入第二个时间：");
14     scanf_s("%d:%d", &hour2, &minute2);
15 
16     int t1 = hour1 * 60 + minute1;
17     int t2 = hour2 * 60 + minute2;
18 
19     int t = t1 - t2;
20 
21     printf("时间差是%d小时%d分钟。\n", t / 60, t % 60);
22 
23     return 0;
24 }

 1 #include<stdio.h>
 2 
 3 int main(void)
 4 {
 5     /*
 6         计算两个时间的时间差
 7     */
 8     int hour1, minute1;
 9     int hour2, minute2;
10 
11     printf("请输入第一个时间：");
12     scanf_s("%d:%d", &hour1, &minute1);
13     printf("请输入第二个时间：");
14     scanf_s("%d:%d", &hour2, &minute2);
15 
16     int t1 = 0;
17     int t2 = 0;
18 
19     if (minute1 >= minute2)
20     {
21         t1 = hour1 - hour2;
22         t2 = minute1 - minute2;
23     }
24     else
25     {
26         t1 = hour1 - 1 - hour2;
27         t2 = minute1 + 60 - minute2;
28     }
29 
30     printf("时间差是%d小时%d分钟。\n", t1, t2);
31 
32     return 0;
33 }

 

posted @ 2019-10-29 11:06  jason2018  阅读(558)  评论(0)    收藏  举报