ppt 例题8 多重背包3

物品   1       2          3        4         5       6

价值   1       2          3        4         5       6

个数   4        7          4        5         9       1

      

 

0	1	2	3	4	5	6	7	8	9	10	11	12	13	14	15	16	17	18	19	20	21	22	23	24	25	26	27	28
1	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0

 

 dp[0] = 1;

 

 

 

 

 

 

 

 

 

 

 物品种类  i= 1

0	1	2	3	4	5	6	7	8	9	10	11	12	13	14	15	16	17	18	19	20	21	22	23	24	25	26	27	28
1	1	1	1	1	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0

 初值 价值 j=0          

价值为v[i=1]               t=j +k*v[i]   1  2  3  4

                                     t=0 +      1  *  1                                                  

                                                           t=0+      2 *   1        

                                                           t=0 +      3 *   1  

                                                           t=0 +      4 *   1           

                                                              j=0     c[i]

 

 

 

 

 

 

 

 

 

 

 

j= 4  3   2  1  

                                    j=4

价值为v[i=2]               t=j +k*v[i]          t  6  8 10 12 14  16  18

                                                          t=4 +      1  *  2                                                  

                                                           t=4 +      2 *   2            

                                                           t=4 +      3 *   2

            

                                                           t=4 +      7 *   2            

                                                                         c[i]

 

 

 

0	1	2	3	4	5	6	7	8	9	10	11	12	13	14	15	16	17	18	19	20	21	22	23	24	25	26	27	28
1	1	1	1	1	0	1	0	1	0	1	0	1	0	1	0	1	0	1	0	0	0	0	0	0	0	0	0	0

 

 

 

                                   j=3

价值为v[i=2]               t=j +k*v[i]          t  5  7   9  11   13  15  17

                                                          t=3 +      1  *  2                                                  

                                                           t=3 +      2 *   2            

                                                           t=3 +      3 *   2

            

                                                           t=3 +      7 *   2            

                                                                         c[i]

 

 

 

 

 

                                   j=2

价值为v[i=2]               t=j +k*v[i]          t  4  6   8  10   12  14  16

                                                          t=2 +      1  *  2                                                  

                                                           t=2 +      2 *   2            

                                                           t=2 +      3 *   2

            

                                                           t=2 +      7 *   2            

                                                                         c[i]

 

 

 

 

 

 

                              j=1

价值为v[i=2]               t=j +k*v[i]          t  3   5   7   9   11  13  15

 

                                                          t=1 +      1  *  2                                                  

                                                           t=1 +      2 *   2            

                                                           t=1 +      3 *   2

         

 

                                                           t=2 +      7 *   2            

 

                                                                         c[i]

 

 

 

 

 

0	1	2	3	4	5	6	7	8	9	10	11	12	13	14	15	16	17	18	19	20	21	22	23	24	25	26	27	28
1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	0	0	0	0	0	0	0	0	0	0