第三次作业

1.

2.在判断是否有多余可除数时设置为return ( two % one == 0 || two % one == 4);此时t2 = ( n = 5)更容易发现错误。

3.(1,2,11,12,13,14)

4.NC:{1,2,3,4,5,6,7,8,9,10,11,12,13,14}
TP:[1,2,3,4,5,6,8,5,6,7,9,10,2,11,12,13,12,14]

EC:{1,2},{2,3},{2,11}
{3,4},{4,5},{5,6},{5,9}
{6,8},{6,7},{8,5},{7,9}
{9,2},{9,10},{10,2}
{11,12},{12,13},{12,14},{13,12}
TP:[1,2,3,4,5,6,8,5,9,2,11,12,13,12,14]
[1,2,3,4,5,6,7,9,10,2,11,12,13,12,14]

PP:[1,2,3,4,5,6,7,9,10]
[1,2,3,4,5,6,7,8]
[1,2,11,12,13]
[1,2,11,12,14]
[2,3,4,5,6,7,9,10,2]
[3,4,5,6,7,9,10,2,3]
[3,4,5,6,7,9,10,2,11,12,13]
[3,4,5,6,7,9,10,2,11,12,14]
[4,5,6,7,9,10,2,3,4]
[5,6,7,9,10,2,3,4,5]
[5,6,8,5]
[6,7,9,10,2,3,4,5,6]
[6,8,5,9,10,2,11,12,13]
[6,8,5,9,10,2,11,12,14]
[6,8,5,6]
[7,9,10,2,3,4,5,6,7]
[8,5,6,9]
[9,10,2,3,4,5,6,7,9]
[10,2,3,4,5,6,7,9,10]
[12,13,12]
[13,12,13]
[13,12,14]

5.TP:[1,2,3,4,5,6,8,5,9,2,11,12,13,12,14]
[1,2,3,4,5,6,7,9,10,2,11,12,13,12,14]

posted on 2018-03-25 19:33  衍光  阅读(76)  评论(0)    收藏  举报