LintCode

生成一个 n * m 的二维矩阵矩阵

'''
n = int(input())
m = int(input())
array = [[0 for _ in range(m)] for _ in range(n)]
'''

遍历打印字典中的键值对
'''
for key, value in dict_in.items():
print(f'{key}: {value}')
'''

字符串标题化(首字母大写)
'''
def title_str(str_in: str) -> str:
titly_str = str_in.title()
return titly_str
'''

列表转为字典
'''
i = ['a', 'b']
l = [1, 2]
print (dict(zip(i,l)))
'''

posted @ 2021-07-06 00:23  17。  阅读(80)  评论(0)    收藏  举报