实验六
task3
task3_1.cpp:
#include <iostream> #include <fstream> #include <array> #define N 5 int main() { using namespace std; array<int, N> x {97, 98, 99, 100, 101}; ofstream out; out.open("data1.dat", ios::binary); if(!out.is_open()) { cout << "fail to open data1.dat\n"; return 1; } out.write(reinterpret_cast<char *>(&x), sizeof(x)); out.close(); }
task3_2.cpp:
#include <iostream> #include <fstream> #include <array> #define N 5 int main() { using namespace std; array<char, N> x; ifstream in; in.open("data1.dat", ios::binary); if(!in.is_open()) { cout << "fail to open data1.dat\n"; return 1; } in.read(reinterpret_cast<char *>(&x), sizeof(x)); in.close(); for(auto i = 0; i < N; ++i) cout << x[i] << ", "; cout << "\b\b \n"; }
task4
Vector.hpp:
#pragma once using std::cout; using std::endl; template <typename T> class Vector { private: int size; T* p; public: Vector(int); Vector(int, T); Vector(const Vector<T>& x); ~Vector(); int get_size() const; T& at(int x); T& operator[](int x); template <typename T1> friend void output(Vector<T1>& x); }; template <typename T> Vector<T>::Vector(int n) : size{ n } { p = new T[n]; } template <typename T> Vector<T>::Vector(int n, T x) : size{ n } { p = new T[n]; for (int i = 0; i < n; i++) { p[i] = x; } } template <typename T1> Vector<T1>::Vector(const Vector<T1>& x) : size{ x.size } { p = new T1[size]; for (auto i = 0; i < size; i++) { p[i] = x.p[i]; } } template <typename T> Vector<T>::~Vector() { delete[] p; } template <typename T> int Vector<T>::get_size()const { return size; } template <typename T> T& Vector<T>::at(int x) { return p[x]; } template<typename T> T& Vector<T>::operator[](int x) { return p[x]; } template<typename T1> void output(Vector<T1>& x) { for (int i = 0; i < x.size; i++) cout << x.p[i] << " "; cout << endl; }
task4.cpp:
#include <iostream> #include "Vector.hpp" void test() { using namespace std; int n; cin >> n; Vector<double> x1(n); for (auto i = 0; i < n; ++i) x1.at(i) = i * 0.7; output(x1); Vector<int> x2(n, 42); Vector<int> x3(x2); output(x2); output(x3); x2.at(0) = 77; output(x2); x3[0] = 999; output(x3); } int main() { test(); }
task5:
#include<iostream> #include <fstream> #include<iomanip> using namespace std; void output(ostream& out) { char i,m; int p, k; out << " "; for (i = 'a'; i <= 'z'; i++) { out << setw(2) << i; } out << endl; for (k = 1; k <= 26; k++) { out << setw(2) << k; for (p = k; p < k + 26; p++) { m = 'A' + p % 26; out << setw(2) << m; } out << endl; } } int main() { output(cout); ofstream out; out.open("cipher_key.txt"); if (!out.is_open()) { cout << "fail to open file cipher_key.txt to write" << endl; return 0; } output(out); out.close(); }