chatgpt风险检测


difficulty = int("061a80", 16)
print(difficulty)
difficulty = hex(difficulty).replace("0x","")
dl = len(difficulty)
if dl <= 2:
    print("风险")
elif dl == 3:
    print("中等")
elif dl == 4:
    print("良好")
else:
    print("优秀")

# POST https://chatgpt.com/backend-api/sentinel/chat-requirements/prepare
# POST https://chatgpt.com/backend-api/sentinel/req
# POST https://realtime.chatgpt.com/v1/vp/status
# {"proofofwork":{"required":true,"seed":"0.8643376005715413","difficulty":"06e490"}}

posted @ 2026-03-08 20:01  Naihe\  阅读(39)  评论(0)    收藏  举报
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