数7 ,0~100中有7的跳过

<script>
for(i = 0; i <= 100; i++) {
var a = parseInt(i % 10);
var b = parseInt((i % 100) / 10);
if(i % 7 == 0 || a == 7 || b == 7||i==0) {
continue
}
document.write(i + "&nbsp")
}
</script>

posted @ 2018-12-13 10:47  掠影浮华  阅读(240)  评论(0)    收藏  举报