#include <stdio.h>
#define N 10
typedef
struct {
char isbn[20];
char name[80];
char author[80];
double sales_price;
int sales_count;
} Book;
void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);
int main() {
Book x[N]
= {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
{
"978-7-308-17047-5", "自由与爱之地:入以色列记", "云也退", 49 , 30},
{
"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
{
"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
{
"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
{
"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
{
"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
{
"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
{
"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
{
"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
printf(
"图书销量排名(按销售册数): \n");
sort(x, N);
output(x, N);
printf(
"\n图书销售总额: %.2f\n", sales_amount(x, N));
return 0;
}
void output(Book x[], int n) {
int i;
printf(
"%-20s %-30s %-20s %-10s %-10s\n","ISBN号","书名", "作者", "售价", "销售册数");
for (i=0;i<n;i++) {
printf(
"%-20s %-30s %-20s %-10.2f %-10d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
}
}
void sort(Book x[], int n) {
int i, j;
for (i = 0; i < n - 1 ; i++) {
for (j = 0; j < n - 1 - i; j++) {
if (x[j].sales_count < x[j + 1].sales_count) {
Book temp
= x[j];
x[j]
= x[j+1];
x[j
+1] = temp;
}
}
}
}
double sales_amount(Book x[], int n) {
double sum = 0;
int i;
for (i = 0; i < n; i++) {
sum
+= x[i].sales_price * x[i].sales_count;
}
return sum;
}
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#include <stdio.h>
typedef struct {
int year;
int month;
int day;
} Date;
void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);
void test1() {
Date d;
int i;
printf("输入日期:(以形如2024-12-16这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&d);
printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
}
}
void test2() {
Date Alice_birth, Bob_birth;
int i;
int ans;
printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&Alice_birth);
input(&Bob_birth);
ans = compare_dates(Alice_birth, Bob_birth);
if(ans == 0)
printf("Alice和Bob一样大\n\n");
else if(ans == -1)
printf("Alice比Bob大\n\n");
else
printf("Alice比Bob小\n\n");
}
}
int main() {
printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
test1();
printf("\n测试2: 两个人年龄大小关系\n");
test2();
}
void input(Date *pd) {
scanf("%d-%d-%d-", &(pd->year),&(pd->month),&(pd->day));
}
int day_of_year(Date d) {
int days_per_month[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int days = d.day;
int i;
if ((d.year % 4 == 0 && d.year % 100 != 0) || (d.year % 400 == 0)) {
days_per_month[2] = 29;
}
for (i = 1; i < d.month;i++) {
days += days_per_month[i];
}
return days;
}
int compare_dates(Date d1, Date d2) {
int year1 = d1.year;
int year2 = d2.year;
int day1 = day_of_year(d1);
int day2 = day_of_year(d2);
if (year1 < year2) {
return -1;
}
else if (year1 > year2) {
return 1;
}
else if (day1 < day2) {
return -1;
}
else if (day1 > day2) {
return 1;
}
else {
return 0;
}
}
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#include <stdio.h>
#include <string.h>
typedef struct {
char name[20];
char phone[12];
int vip;
} Contact;
// 函数声明
void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);
#define N 10
int main() {
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt, i;
char name[20];
printf("显示原始通讯录信息: \n");
output(list, N);
printf("\n输入要设置的紧急联系人个数: ");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for(i = 0; i < vip_cnt; ++i) {
scanf("%s", name);
set_vip_contact(list, N, name);
}
printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
display(list, N);
return 0;
}
void set_vip_contact(Contact x[], int n, char name[]) {
int i;
for (i = 0;i < n;i++) {
if (strcmp(x[i].name,name) == 0){
x[i].vip = 1;
}
}
}
void display(Contact x[], int n) {
int i,j=0;
Contact t;
for(i=0;i<n-1;i++){
for(j=0;j<n-i-1;j++){
if(x[j].vip<x[j+1].vip){
t=x[j];
x[j]=x[j+1];
x[j+1]=t;
}
else if(x[j].vip==x[j+1].vip&&strcmp(x[j].name,x[j+1].name)>0){
t=x[j];
x[j]=x[j+1];
x[j+1]=t;![]()
#include <stdio.h>
#include <string.h>
enum Role {admin, student, teacher};
typedef struct {
char username[20];
char password[20];
enum Role type;
} Account;
void output(Account x[], int n);
int main() {
Account x[] = {{"A1001", "123456", student},
{"A1002", "123abcdef", student},
{"A1009", "xyz12121", student},
{"X1009", "9213071x", admin},
{"C11553", "129dfg32k", teacher},
{"X3005", "921kfmg917", student}};
int n;
n = sizeof(x)/sizeof(Account);
output(x, n);
return 0;
}
void output(Account x[], int n) {
int i, j;
for (i = 0; i < n;i++) {
printf("%-10s",x[i].username);
for (j = 0; j < strlen(x[i].password);j++) {
printf("*");
}
printf("%-10s","");
if (x[i].type == admin) {
printf("%-20s\n","admin");
}
else if (x[i].type == student){
printf("%-20s\n","student");
}
else if (x[i].type == teacher){
printf("%-20s\n","teacher");
}
}
}
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}
}
}
output(x,n);
}
void output(Contact x[], int n) {
int i;
for(i = 0; i < n; ++i) {
printf("%-10s%-15s", x[i].name, x[i].phone);
if(x[i].vip)
printf("%5s", "*");
printf("\n");
}
}