每瓶啤酒2元，2个空酒瓶或4个瓶盖可换1瓶啤酒,10元最多可喝多少瓶啤酒？ 

 1 //---------------------------------------------------------------------------
 2 
 3 #include <vcl.h>
 4 #pragma hdrstop
 5 #include <stdio.h>
 6 //---------------------------------------------------------------------------
 7 #define PRICE  2
 8 #pragma argsused
 9 int main(int argc, char* argv[])
10 {
11   int money = 10 ;
12   int sum,bottle,cap,temp;
13 
14   sum =  (int)(money/PRICE);
15   bottle = sum;
16   cap = sum;
17 
18   while( bottle >= 2 || cap >=4 )
19   {
20     temp = (int)(bottle/2);
21     sum += temp;
22     bottle = temp+bottle-temp*2;
23     cap += temp;
24 
25     temp = (int)(cap/4);
26     sum += temp;
27     cap = temp+cap-temp*4;
28     bottle += temp;
29 
30   }
31   printf("%d元可以喝%d瓶酒\n",money,sum);
32   for(;;);
33   return 0;
34 }
35 //---------------------------------------------------------------------------

 

posted @ 2016-01-24 18:44  十的负六次  阅读(414)  评论(0)    收藏  举报