# 用户消费总金额 2000以下 2000-4000 4000-6000 查询连续数字,统计个数

createtable tb_1(
id
int,
xiaofei
money,
userid
int,
datetime
)
insertinto tb_1 values(1, 880, 1, getdate())
insertinto tb_1 values(2, 950, 2, getdate())
insertinto tb_1 values(3, 740, 1, getdate())
insertinto tb_1 values(4, 254, 4, getdate())
insertinto tb_1 values(5, 2541, 5, getdate())
insertinto tb_1 values(6, 80, 3, getdate())
insertinto tb_1 values(7, 3870, 1, getdate())
insertinto tb_1 values(8, 100, 2, getdate())
insertinto tb_1 values(9, 180, 3, getdate())
insertinto tb_1 values(10, 3240, 6, getdate())

select*from tb_1

select userid, sum(xiaofei) as'消费总金额'from tb_1 groupby userid orderbysum(xiaofei) desc

select userid,sum(xiaofei) as'2000以下'from tb_1 groupby userid havingsum(xiaofei) <2000
select userid,sum(xiaofei) as'2000-4000'from tb_1 groupby userid havingsum(xiaofei) between2000and4000
select userid,sum(xiaofei) as'4000-6000'from tb_1 groupby userid havingsum(xiaofei) between4000and6000

droptable tb_1

/*

userid      消费总金额
----------- ---------------------
1           5490.00
6           3240.00
5           2541.00
2           1050.00
3           260.00
4           254.00

(6 行受影响)

userid      2000以下
----------- ---------------------
2           1050.00
3           260.00
4           254.00

(3 行受影响)

userid      2000-4000
----------- ---------------------
5           2541.00
6           3240.00

(2 行受影响)

userid      4000-6000
----------- ---------------------
1           5490.00

(1 行受影响)

*/

--查询连续数字,统计个数

create table tb1(NUM INT)
INSERT INTO tb1
SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 12
UNION ALL SELECT 17
UNION ALL SELECT 18
UNION ALL SELECT 19
UNION ALL SELECT 20
UNION ALL SELECT 25
UNION ALL SELECT 30
go

select * from tb1
drop table tb1,#tb

--sql2000
select num,rid=identity(int,1,1into #tb from tb1
select min(num) minNum,max(num) maxNum,count(1) cnt
from #tb
group by (num-rid)
having count(*> 1

--sql2005

select 开始=min(num),结束=max(num),count(1) cnt from     (
select row_number()over (order by num) as rid,* from tb1
) a group by num-rid having(count(1)>1)

--结果：
--
1        5    5
--
12    12    1
--
17    20    4
--
25    25    1

--30    30    1

posted @ 2010-01-03 11:30 曾祥展 阅读(...) 评论(...) 编辑 收藏