hdu 2066(最短路bellmanFord)

/*
  Name: 最短路(bellmanFord) 
  Copyright: 
  Author: Try_86
  Date: 12/04/12 12:42
  Description: 对每个起始点运行一次bellmanFord,求最短路 
*/

#include <cstdio>
#include <iostream>

using namespace std;

const int N = 1005;
const int M = 500500;
const int MAX = 1000000000;

int dis[N], ss[N], ds[N];
struct edge {

    int u;
    int v;
    int w;
}e[M];

void init(int vs, int s) {
    for (int i=1; i<=vs; ++i) dis[i] = MAX;
    dis[s] = 0;
    return ;
} 

void relax(int u, int v, int w) {
    if (dis[v] > dis[u] + w) dis[v] = dis[u] + w;
    return ;
}

void bellmanFord(int es, int vs, int s) {
    init(vs, s);
    for (int i=1; i<vs; ++i) {
        for (int j=0; j<es; ++j) relax(e[j].u, e[j].v, e[j].w);
    }
    return ;
}

int main() {
    int t, s, d;
    while (scanf("%d%d%d", &t, &s, &d) != EOF) {
        int vs = 0;
        for (int i=0; i<t; ++i) {
            scanf ("%d%d%d", &e[i].u, &e[i].v, &e[i].w);
            e[i+t].v = e[i].u;
            e[i+t].u = e[i].v;
            e[i+t].w = e[i].w;
            if (vs < e[i].u) vs = e[i].u;
            if (vs < e[i].v) vs = e[i].v;
        }
        for (int i=0; i<s; ++i) scanf ("%d", &ss[i]);
        for (int i=0; i<d; ++i) scanf ("%d", &ds[i]);
        int mins = MAX;
        for (int i=0; i<s; ++i) {
            bellmanFord(t<<1, vs, ss[i]);
            for (int j=0; j<d; ++j) {
                if (mins > dis[ds[j]]) mins = dis[ds[j]];
            }
        }
        printf ("%d\n", mins);
    }
    return 0;
}

 

posted on 2012-04-12 12:47  Try86  阅读(235)  评论(0编辑  收藏  举报