PAT甲级——A1051 Pop Sequence

Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and pop randomly. You are supposed to tell if a given sequence of numbers is a possible pop sequence of the stack. For example, if M is 5 and N is 7, we can obtain 1, 2, 3, 4, 5, 6, 7 from the stack, but not 3, 2, 1, 7, 5, 6, 4.

Input Specification:

Each input file contains one test case. For each case, the first line contains 3 numbers (all no more than 1000): M (the maximum capacity of the stack), N (the length of push sequence), and K (the number of pop sequences to be checked). Then K lines follow, each contains a pop sequence of N numbers. All the numbers in a line are separated by a space.

Output Specification:

For each pop sequence, print in one line "YES" if it is indeed a possible pop sequence of the stack, or "NO" if not.

Sample Input:

5 7 5
1 2 3 4 5 6 7
3 2 1 7 5 6 4
7 6 5 4 3 2 1
5 6 4 3 7 2 1
1 7 6 5 4 3 2

Sample Output:

YES
NO
NO
YES
NO


 1 #include <iostream>
 2 #include <stack>
 3 using namespace std;
 4 int M, N, K;
 5 int main()
 6 {
 7     cin >> M >> N >> K;    
 8     for (int i = 0; i < K; ++i)
 9     {
10         stack<int>s;
11         int a, b = 1, flag = 1;
12         for (int j = 0; j < N; ++j)
13         {
14             cin >> a;
15             while (s.size() < M && (s.empty() || s.top() != a))
16                 s.push(b++);
17             if (s.top() == a)
18                 s.pop();
19             else
20                 flag = 0;
21         }
22         if (flag == 1)
23             cout << "Yes" << endl;
24         else
25             cout << "No" << endl;
26     }
27     return 0;
28 }

 

posted @ 2019-08-01 10:06  自由之翼Az  阅读(136)  评论(0编辑  收藏  举报