浏览器地址截取
摘要:var urlData = location.search.split('?')[1].split("&"); var datatype = location.search.split('?')[1].split("=")[1]
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posted @ 2017-05-24 14:23
posted @ 2017-05-24 14:23
posted @ 2017-05-23 15:18
posted @ 2017-05-23 15:18