摘要:
#include <stdio.h>void heapify(int* intp, unsigned idx, unsigned nr){ unsigned j = idx; while (1) { unsigned i = idx * 2 + 1; if (nr > i && intp[i] > intp[j]) { j = i; } ++i; if (nr > i && intp[i] > intp[j]) { j = i; } ... 阅读全文
posted @ 2013-02-22 15:43
zylthinking
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