实验4 类与数组、指针

实验任务5

vectorInt.hpp

#pragma once

#include<iostream>
#include<cassert>

using namespace std;

class vectorInt {
public:
    vectorInt(int n);
    vectorInt(int n, int value);
    vectorInt(const vectorInt& vi);
    ~vectorInt();
    int& at(int index);
    int get_size();
    friend void output(const vectorInt& vi);
private:
    int size;
    int* p;
};
vectorInt::vectorInt(int n) :size{ n } {
    cout << "constructor 1 called." << endl;
    p = new int[n];
}
vectorInt::~vectorInt() {
    cout << "destructor called." << endl;
    delete p;
}
int &vectorInt::at(int index) {
    assert(index >= 0 && index < size);
    return p[index];
}
vectorInt::vectorInt(const vectorInt& vi) :size{vi.size} {
    cout << "copy constructor called." << endl;
    p = new int[size];
    for (auto i = 0; i < size; i++)
        p[i] = vi.p[i];
}
vectorInt::vectorInt(int n, int value) :size{ n } {
    cout << "constructor 2 called." << endl;
    p = new int[n];
    for (auto i = 0; i < n; i++) {
        p[i] = value;
    }
}
int vectorInt::get_size() {
    return size;
}
void output(const vectorInt& vi) {
    for (auto i = 0; i < vi.size; i++)
        cout << vi.p[i] << ", ";
    cout << "\b\b \n";
}

tast5.cpp

#include<iostream>
#include"vectorInt.hpp"

void test() {
    using namespace std;

    int n;
    cin >> n;

    vectorInt x1(n);
    for (auto i = 0; i < n; ++i)
        x1.at(i) = i * i;

    output(x1);

    vectorInt x2(n, 42);
    vectorInt x3(x2);
    output(x2);
    output(x3);

    x2.at(0) = 77;
    output(x2);
    output(x3);
}
int main() {
    test();
}

运行测试结果:

 实验任务6

Matrix.hpp

#pragma once
#include<iostream>

using std::cout;
using std::endl;

class Matrix {
public:
    Matrix(int n);    // 构造函数,构造一个n*n的矩阵
    Matrix(int n, int m);// 构造函数,构造一个n*m的矩阵
    Matrix(const Matrix& x);// 复制构造函数,使用已有的矩阵X构造
    ~Matrix();//析构函数

    void set(const double* pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值
    void set(int i, int j, int value);//设置矩阵第i行第j列元素值为value
    double at(int i, int j)const;// 返回矩阵第i行第j列元素的值
    int get_lines()const {return lines; }//返回矩阵行数
    int get_cols()const { return cols; }//返回矩列数
    void print() const;// 按行打印输出矩阵

private:
    int lines;
    int cols;
    double* p;
};
Matrix::Matrix(int n) :lines{ n }, cols{ n } {
    //cout << "constructor 1 called." << endl;
    p = new double[n * n];
}
Matrix::Matrix(int n, int m) :lines{ n }, cols{ m } {
    //cout << "constructor 2 called." << endl;
    p = new double[n * m];
}
Matrix::Matrix(const Matrix& x) :lines{ x.lines }, cols{x.cols} {
    //cout << "copy constructor called." << endl;
    p = new double[lines * cols];
    for (auto i = 0; i < lines * cols; i++) {
        p[i] = x.p[i];
    }    
}
Matrix::~Matrix() {
    //cout<< "destructor called." << endl;
    delete p;
}
void Matrix::set(const double* pvalue) {
    for (auto i = 0; i < lines * cols; i++) {
        p[i] = pvalue[i];
    }
}
void Matrix::print()const {
    int k = 0;
    for (auto j = 0; j < lines; j++) {
        for (auto i = 0; i < cols; i++) {
            cout << p[k++] << ", ";
        }
        cout << "\b\b \n";
    }
}
void Matrix::set(int i, int j, int value) {
    p[i*cols+j] = value;
}
double Matrix::at(int i, int j)const{
    return p[i*cols+j];
}

task6.cpp

#include<iostream>
#include"Matrix,hpp.h"

void test() {
    using namespace std;

    double x[] = { 1,2,3,4,5,6 };

    Matrix m1(3, 2);
    m1.set(x);
    m1.print();
    cout << "the first line is: " << endl;
    cout << m1.at(0, 0) << " " << m1.at(0, 1) << endl;
    cout << endl;

    Matrix m2(2, 3);
    m2.set(x);
    m2.print();
    cout << "the first line is: " << endl;
    cout << m2.at(0, 0) << " " << m2.at(0, 1) << " " << m2.at(0, 2) << endl;
    cout << endl;

    Matrix m3(m2); 
    m3.set(0, 0, 999); 
    m3.print();
    cout << endl;
    
}
int main()
{
    test();
}

运行测试结果:

改变数据:

运行测试结果:

实验总结:

实验6的空间在获取时是一维数组的的形式,需要将二维数组转化为一维数组进行存储,设置具体行列数时需要根据具体的行列进行运算,根据行序为主序,具体的地址为i*cols+j。

posted @ 2022-11-05 21:55  kierborn  阅读(15)  评论(0)    收藏  举报