摘要: NSArray *arr = @[@"beijing",@"shanghai",@"shenzhen",@"guangzhou",@"hangzhou",@"nanchang"]; NSString *str = @"nan"; NSPredicate *predicate = [NSPredica 阅读全文
posted @ 2016-06-05 14:37 zshl 阅读(805) 评论(0) 推荐(0)