1元汽水，2空瓶换1瓶的问题

int main()
{
//方案1
int pay = 0;
int sum = 0;
scanf("%d", &pay);
while (pay)
{
sum += pay;
pay /= 2;
}
sum = sum + 1;
printf("%d\n", sum);
//方案2
int money = 0;//多少钱
int total = 0;//喝的瓶数
int empty = 0;//空瓶数
scanf("%d", &money);
total = money;
if (total > 0)
{
printf("%d", 2 * total - 1);
}
else
printf("0");
//方案3
empty = money;

while (empty >= 2)
{
total += empty / 2;
empty = empty / 2 + empty % 2;
}

printf("%d", total);
return 0;
}