实验4
//task1_1.c// #include<stdio.h> #define N 4 int main() { int a[N] = {2,0,2,2}; char b[N] = {'2','0','2','2'}; int i; printf("sizeof(int) = %d\n",sizeof(int)); printf("sizeof(char) = %d\n",sizeof(char)); printf("\n"); //输出数组a中每个元素的地址、值 for(i=0;i<N;++i) printf("%p: %d\n",&a[i],a[i]); printf("\n"); //输出数组b中每个元素的地址、值 for(i=0;i<N;++i) printf("%p: %c\n",&b[i],b[i]); printf("\n"); //输出数组名a和b对应的值 printf("a = %p\n",a); printf("b = %p\n",b); return 0; }

1、int型数据a,在内存中是连续存放的,每个元素占用4个内存字节单元;
2、char型数据b,在内存中是连续存放的,每个元素占用1个内存字节单元;
3、数组名a对应的值,和&a[0]是一样,数组名b对应的值,和&b[0]是一样;
//task1_2.c// #include<stdio.h> #define N 2 #define M 3 int main() { int a[N][M] = {{1,2,3},{4,5,6}}; char b[N][M] = {{'1','2','3'},{'4','5','6'}}; int i,j; printf("sizeof(int) = %d\n",sizeof(int)); printf("sizeof(char) = %d\n",sizeof(char)); printf("\n"); //输出二维数组中每个元素的地址、值 for(i=0;i<N;++i) for(j=0;j<M;++j) printf("%p: %d\n",&a[i][j],a[i][j]); printf("\n"); //输出二维数组中每个元素的地址、值 for(i=0;i<N;++i) for(j=0;j<M;++j) printf("%p: %c\n",&b[i][j],b[i][j]); return 0; }

1、int型二维数组a,在内存中是“按行连续存放”的,每个元素占用4个内存字节单元;
2、char型二维数组b,在内存中是“按行连续存放”的,每个元素占用1个内存字节单元;
//task2.c switch实现// #include<stdio.h> int days_of_year(int year,int month,int day); int main() { int year,month,day; int days; while(scanf("%d%d%d",&year,&month,&day) != EOF) { days = days_of_year(year,month,day); printf("%4d-%02d-%02d是这一年的第%d天.\n\n",year,month,day,days); } return 0; } int days_of_year(int year,int month,int day) { int s=0; switch(month) { case 12: s+=30; case 11: s+=31; case 10: s+=30; case 9: s+=31; case 8: s+=31; case 7: s+=30; case 6: s+=31; case 5: s+=30; case 4: s+=31; case 3: s+=28; case 2: s+=31; case 1: s+=day; } if((year%4==0 && year%100 !=0 || year%400==0)&&month>=3) s++; return s; }

//task.2.c数组实现// #include<stdio.h> int days_of_year(int year,int month,int day); int main() { int year,month,day; int days; while(scanf("%d%d%d",&year,&month,&day) != EOF) { days = days_of_year(year,month,day); printf("%4d-%02d-%02d是这一年的第%d天.\n\n",year,month,day,days); } return 0; } int days_of_year(int year,int month,int day) { int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31}; int i,j,s=0; for(j=0;j<month;j++) { s+=a[j]; } s+=day; if(month>=3) { if((year % 4 ==0 )&&(year % 100 != 0)||(year%400==0)) s+=1; } return s; }

//task.3// #include<stdio.h> #define N 5 //函数声明 void input(int x[],int n); void output(int x[],int n); double average(int x[],int n); void sort(int x[],int n); int main() { int scores[N]; double ave; printf("录入%d个分数:\n",N); input(scores,N); printf("\n输出课程分数:\n"); output(scores,N); printf("\n课程分数处理:计算均分、排序...\n"); ave = average(scores,N); sort(scores,N); printf("\n输出课程平均分:%.2f\n",ave); printf("\n输出课程分数(高->低):\n"); output(scores,N); return 0; } //函数定义 //输入n个整数保存到整型数组x中 void input(int x[],int n) { int i; for(i=0;i<n;++i) scanf("%d",&x[i]); } //输出整型数组x中n个元素 void output(int x[],int n) { int i; for(i=0;i<n;++i) printf("%d ",x[i]); printf("\n"); } double average(int x[],int n) { int i; double s=0,average; for(i=0;i<n;++i) { s+=x[i]; } average=s/n; return average; } void sort(int x[],int n) { int i,j,t; for(i=0;i<n-1;++i) { for(j=0;j<n-i-1;++j) if(x[j]<x[j+1]) { t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } }

//task.4.c// #include<stdio.h> void dec2n(int x,int n); int main() { int x; printf("输入一个十进制整数; "); scanf("%d",&x); dec2n(x,2); dec2n(x,8); dec2n(x,16); return 0; } void dec2n(int x,int n) { int i=0,j,a[100]; char b[100]; if(n==16) { for(i=0;x!=0;i++,j++) { if(x%16==10) b[i]='A'; else if(x%16==11) b[i]='B'; else if(x%16==12) b[i]='C'; else if(x%16==13) b[i]='D'; else if(x%16==14) b[i]='E'; else if(x%16==15) b[i]='F'; else b[i]=x%16+'0'; x=x/16; } for(j=i-1;j>=0;j--) printf("%c",b[j]); printf("\n"); } else { do{ a[i] = x%n; x =x/n; i++; j++; }while(x!=0); for(j=i-1;j>=0;j--) printf("%d",a[j]); printf("\n"); } }


//task.5// #include<stdio.h> int main() { int n,i,j; printf("Enter n:"); while (scanf("%d",&n)!=EOF) { int a[n][n]; for(i=0;i<n;i++) { for(j=i;j<n;j++) {a[i][j]=i+1;} } for(j=0;j<n;j++) { for(i=j;i<n;i++) {a[i][j]=j+1;} } for(i=0;i<n;i++) { for(j=0;j<n;j++) { printf("%d ",a[i][j]); } printf("\n"); } printf("\n\nEnter n:"); } return 0; }

//task.6// #include<stdio.h> #define N 80 int main() { char views1[N]="hey,c,i hate u."; char views2[N]="hey,c,i love u."; int i,j; char t; printf("original views:\n"); printf("views1:\n"); for(j=0;j<N;j++) printf("%c",views1[j]); printf("\n"); printf("views2:\n"); for(j=0;j<N;j++) printf("%c",views2[j]); printf("\n"); printf("swapping...\n"); for(i=0;i<N;i++) { t=views1[i]; views1[i]=views2[i]; views2[i]=t; } printf("views1:"); for(j=0;j<N;j++) printf("%c",views1[j]); printf("\n"); printf("views2:"); for(j=0;j<N;j++) printf("%c",views2[j]); }

//task.7// #include<stdio.h> #include<string.h> #define N 5 #define M 20 void bubble_sort(char str[][M],int n); int main() { char name[][M] = {"Bob","Bill","Joseph","Taylor","George"}; int i; printf("输出初始名单:\n"); for(i=0;i<N;i++) printf("%s\n",name[i]); printf("\n排序中...\n"); bubble_sort(name,N); printf("\n按字典输出名单:\n"); for(i=0;i<N;i++) printf("%s\n",name[i]); return 0; } void bubble_sort(char str[][M],int n) { int i,j; char temp[M]; for(i=0;i<n-1;i++) { for(j=i+1;j<n;j++) if(strcmp(str[j],str[i])<0) { strcpy(temp,str[i]); strcpy(str[i],str[j]); strcpy(str[j],temp); } } }

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