thread互斥测试

编译运行附件中的代码,并说明程序的功能

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <ctype.h>

struct arg_set {
char *fname;
int count;
};

struct arg_set *mailbox = NULL;
pthread_mutex_t lock = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t flag = PTHREAD_COND_INITIALIZER;

void *count_words(void *);
int main(int argc, char *argv[])
{
pthread_t t1, t2;
struct arg_set args1, args2;
int reports_in = 0;
int total_words = 0;

if ( argc != 3 ){
printf("usage: %s file1 file2\n", argv[0]);
exit(1);
}

args1.fname = argv[1];
args1.count = 0;
pthread_create(&t1, NULL, count_words, (void *) &args1);

args2.fname = argv[2];
args2.count = 0;
pthread_create(&t2, NULL, count_words, (void *) &args2);

pthread_mutex_lock(&lock);
while( reports_in < 2 ){
printf("MAIN: waiting for flag to go up\n");
pthread_cond_wait(&flag, &lock);
printf("MAIN: Wow! flag was raised, I have the lock\n");
printf("%7d: %s\n", mailbox->count, mailbox->fname);
total_words += mailbox->count;
if ( mailbox == &args1)
pthread_join(t1,NULL);
if ( mailbox == &args2)
pthread_join(t2,NULL);
mailbox = NULL;
pthread_cond_signal(&flag);
reports_in++;
}
pthread_mutex_unlock(&lock);

printf("%7d: total words\n", total_words);
}
void *count_words(void *a)
{
struct arg_set *args = a;
FILE *fp;
int c, prevc = '\0';

if ( (fp = fopen(args->fname, "r")) != NULL ){
while( ( c = getc(fp)) != EOF ){
if ( !isalnum(c) && isalnum(prevc) )
args->count++;
prevc = c;
}
fclose(fp);
} else
perror(args->fname);
printf("COUNT: waiting to get lock\n");
pthread_mutex_lock(&lock);
printf("COUNT: have lock, storing data\n");
if ( mailbox != NULL ){
printf("COUNT: oops..mailbox not empty. wait for signal\n");
pthread_cond_wait(&flag,&lock);
}
mailbox = args;
printf("COUNT: raising flag\n");
pthread_cond_signal(&flag);
printf("COUNT: unlocking box\n");
pthread_mutex_unlock(&lock);
return NULL;
}

 

 

 

 

 

 

 

 

 

 

 

 

 程序功能:

通过thread互斥来查看两个文件中字符串的数量,一个空格分开算两个,第一个zx.txt文件先获得锁,第二个xx.txt文件则需要等待,当第一个完成之后再进行第二个文件的统计操作,最后输出总结果。

 

posted @ 2022-11-08 20:42  不加糖的酒  阅读(6)  评论(0编辑  收藏  举报