hdu2199(高精度二分模版)
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
Now please try your lucky.
#include<iostream>
#include<math.h>
#include<stdio.h>
using namespace std;
double deal(double x)
{
return 8*pow(x,4)+7*pow(x,3)+2*pow(x,2)+3*x+6;
}
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
double x,sum,l=0,r=100;
scanf("%lf",&sum);
if(sum<deal(0)||sum>deal(100.0))
{
printf("No solution!\n");
continue;
}
else
{
double mid;
int flg=0;
while(r-l>1e-6)
{
mid=(l+r)/2;
if(deal(mid)>sum)
r=mid;
else
l=mid;
}
printf("%.4lf\n",r);
}
}
return 0;
}
朋友们,虽然这个世界日益浮躁起来,只要能够为了当时纯粹的梦想和感动坚持努力下去,不管其它人怎么样,我们也能够保持自己的本色走下去。

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