1 /** 2 * Definition for a binary tree node. 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 static int wing=[]() 11 { 12 std::ios::sync_with_stdio(false); 13 cin.tie(NULL); 14 return 0; 15 }(); 16 17 class Solution 18 { 19 public: 20 bool isSymmetric(TreeNode* root) 21 { 22 if(root==NULL) 23 return true; 24 return IsMirror(root->left,root->right); 25 } 26 27 bool IsMirror(TreeNode* p,TreeNode* q) 28 { 29 if(p==NULL&&q==NULL) 30 return true; 31 if(p==NULL||q==NULL) 32 return false; 33 if(p->val!=q->val) 34 return false; 35 return IsMirror(p->left,q->right)&&IsMirror(p->right,q->left); 36 } 37 };
用个镜像函数来递归判定,大树化小树,经典递归