SGU-495 Kids and Prizes 概率DP

  题目链接:http://acm.sgu.ru/problem.php?contest=0&problem=495

  题意:有n个盒子,每个盒子里面放了一个奖品,m个人轮流去选择盒子,如果盒子里面有奖品,就把奖品拿走,盒子留下,否则直接走人。求最后被抽走的奖品数期望。。。

  如果直接考虑用期望来建立DP,复杂度都很高,而且题目精度过高。换一个角度思考,考虑每个奖品不被拿走的概率(1/n)^m,那么不被拿走的期望就是n*(1/n)^m,则拿走的期望n-n*(1/n)^m,复杂度O(1)。还可以考虑f[i]表示第 i 个人拿到奖品的概率,那么1-f[i]就是没有拿到奖品的概率,是对立事件,则f[i]=(1-f[i-1])*f[i-1] + f[i-1]*(f[i-1]-1/n),(1-f[i-1])*f[i-1]表示第 j-1 个人没有拿到奖品,f[i-1]*(f[i-1]-1/n)表示第 j-1 个人拿到奖品了,那么接下来拿到奖品的概率就会减小1/n。。

  O(1):

 1 //STATUS:C++_AC_15MS_320KB
 2 #include <functional>
 3 #include <algorithm>
 4 #include <iostream>
 5 //#include <ext/rope>
 6 #include <fstream>
 7 #include <sstream>
 8 #include <iomanip>
 9 #include <numeric>
10 #include <cstring>
11 #include <cassert>
12 #include <cstdio>
13 #include <string>
14 #include <vector>
15 #include <bitset>
16 #include <queue>
17 #include <stack>
18 #include <cmath>
19 #include <ctime>
20 #include <list>
21 #include <set>
22 #include <map>
23 using namespace std;
24 //#pragma comment(linker,"/STACK:102400000,102400000")
25 //using namespace __gnu_cxx;
26 //define
27 #define pii pair<int,int>
28 #define mem(a,b) memset(a,b,sizeof(a))
29 #define lson l,mid,rt<<1
30 #define rson mid+1,r,rt<<1|1
31 #define PI acos(-1.0)
32 //typedef
33 typedef __int64 LL;
34 typedef unsigned __int64 ULL;
35 //const
36 const int N=130;
37 const int INF=0x3f3f3f3f;
38 const LL MOD=1000000007,STA=8000010;
39 const LL LNF=1LL<<55;
40 const double EPS=1e-9;
41 const double OO=1e30;
42 const int dx[4]={-1,0,1,0};
43 const int dy[4]={0,1,0,-1};
44 const int day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
45 //Daily Use ...
46 inline int sign(double x){return (x>EPS)-(x<-EPS);}
47 template<class T> T gcd(T a,T b){return b?gcd(b,a%b):a;}
48 template<class T> T lcm(T a,T b){return a/gcd(a,b)*b;}
49 template<class T> inline T lcm(T a,T b,T d){return a/d*b;}
50 template<class T> inline T Min(T a,T b){return a<b?a:b;}
51 template<class T> inline T Max(T a,T b){return a>b?a:b;}
52 template<class T> inline T Min(T a,T b,T c){return min(min(a, b),c);}
53 template<class T> inline T Max(T a,T b,T c){return max(max(a, b),c);}
54 template<class T> inline T Min(T a,T b,T c,T d){return min(min(a, b),min(c,d));}
55 template<class T> inline T Max(T a,T b,T c,T d){return max(max(a, b),max(c,d));}
56 //End
57 
58 double n,m;
59 
60 int main(){
61   //  freopen("in.txt","r",stdin);
62     int i,j;
63     while(~scanf("%lf%lf",&n,&m))
64     {
65         printf("%.10lf\n",n*(1-pow((n-1)/n,m)));
66     }
67     return 0;
68 }

  O(m):

 1 //STATUS:C++_AC_15MS_1675KB
 2 #include <functional>
 3 #include <algorithm>
 4 #include <iostream>
 5 //#include <ext/rope>
 6 #include <fstream>
 7 #include <sstream>
 8 #include <iomanip>
 9 #include <numeric>
10 #include <cstring>
11 #include <cassert>
12 #include <cstdio>
13 #include <string>
14 #include <vector>
15 #include <bitset>
16 #include <queue>
17 #include <stack>
18 #include <cmath>
19 #include <ctime>
20 #include <list>
21 #include <set>
22 #include <map>
23 using namespace std;
24 //#pragma comment(linker,"/STACK:102400000,102400000")
25 //using namespace __gnu_cxx;
26 //define
27 #define pii pair<int,int>
28 #define mem(a,b) memset(a,b,sizeof(a))
29 #define lson l,mid,rt<<1
30 #define rson mid+1,r,rt<<1|1
31 #define PI acos(-1.0)
32 //typedef
33 typedef __int64 LL;
34 typedef unsigned __int64 ULL;
35 //const
36 const int N=100010;
37 const int INF=0x3f3f3f3f;
38 const LL MOD=1000000007,STA=8000010;
39 const LL LNF=1LL<<55;
40 const double EPS=1e-9;
41 const double OO=1e30;
42 const int dx[4]={-1,0,1,0};
43 const int dy[4]={0,1,0,-1};
44 const int day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
45 //Daily Use ...
46 inline int sign(double x){return (x>EPS)-(x<-EPS);}
47 template<class T> T gcd(T a,T b){return b?gcd(b,a%b):a;}
48 template<class T> T lcm(T a,T b){return a/gcd(a,b)*b;}
49 template<class T> inline T lcm(T a,T b,T d){return a/d*b;}
50 template<class T> inline T Min(T a,T b){return a<b?a:b;}
51 template<class T> inline T Max(T a,T b){return a>b?a:b;}
52 template<class T> inline T Min(T a,T b,T c){return min(min(a, b),c);}
53 template<class T> inline T Max(T a,T b,T c){return max(max(a, b),c);}
54 template<class T> inline T Min(T a,T b,T c,T d){return min(min(a, b),min(c,d));}
55 template<class T> inline T Max(T a,T b,T c,T d){return max(max(a, b),max(c,d));}
56 //End
57 
58 double f[N];
59 int n,m;
60 
61 int main(){
62  //   freopen("in.txt","r",stdin);
63     int i,j;
64     double ans;
65     while(~scanf("%d%d",&n,&m))
66     {
67         f[0]=1;ans=1;
68         for(i=1;i<m;i++){
69             f[i]=(1-f[i-1])*f[i-1]+f[i-1]*(f[i-1]-1.0/n);
70             ans+=f[i];
71         }
72 
73         printf("%.10lf\n",ans);
74     }
75     return 0;
76 }

 

posted @ 2013-08-12 20:21  zhsl  阅读(423)  评论(0编辑  收藏  举报