php 实现收藏功能

话不多说,先贴代码。

HTML:

<a class = "x" id="{$photo.id}" uid="{$Think.session.uid}" status = "{$collect_pic}" href = "javascript:void(0);">
<if condition = "$collect_num gt 0">
    <span>取消收藏</span>
<else/><span>收藏</span></if></a>

Js:

//点击收藏,实现已收藏
    $('.x').on('click',function(){
        var Oa=$(this);
        var id=Oa.attr('id');//获取图片id属性
        var uid = Oa.attr('uid');//获取用户id
        var status = Oa.attr('status'); //获取收藏状态 1收藏,0取消收藏
        $.post('url',{id:id,uid:uid,status:status},function(msg){
            if(msg.status==1){
                Oa.find("span").text('取消收藏');
                Oa.attr('status','1');
            }else{
                Oa.find("span").text('收藏');
                Oa.attr('status','0');
            }
        },'json')
    })

PHP:

//判断用户是否已收藏该图片
            $data['uid'] = $_SESSION['uid'];
            $data['pid'] = $pid;
            $collect_pic = M('collect')->where($data)->getfield('status');
            $this->collect_num = $collect_num;
            $this->collect_pic = $collect_pic;

//收藏成功
        public function cang(){

            $data['pid'] = isset($_POST['id'])?intval(trim($_POST['id'])):0;
            $data['uid'] = $_SESSION['uid'];
            //默认o收藏 1取消收藏
            $status = isset($_POST['status'])?intval(trim($_POST['status'])):0;
            $db = M('collect');
            if($status == 0){
                //数据组装,忽略
                if(M('collect')->data($collect)->add()){
                    $msg['info'] = "ok";
                    $msg['status'] = 1;
                    $this->ajaxreturn($msg);
                    exit;                
                }else{
                    $msg['info'] = 'fail';
                    $msg['status'] = 1;
                    $this->ajaxreturn($msg);
                }
            }else{
                //取消收藏
                if($db->where($data)->delete()){
                    $msg['info'] = "ok";
                    $msg['status'] = 0;
                    $this->ajaxreturn($msg);
                    exit;
                }else{
                    $msg['info'] = 'fail';
                    $msg['status'] = 0;
                    $this->ajaxreturn($msg);
                }
            }

思路:基本没什么难度,注意细节即可。

posted @ 2017-01-17 16:56  Eden7  阅读(7241)  评论(21编辑  收藏  举报