poj 3761
摘要:
#include<iostream>#include<fstream>using namespace std;#define MOD 20100713long long n,m;long long pow (int k, int n){ long long r = k, ans = 1; while (n) { if (n & 1) ans = (ans * r) % MOD; r = (r * r) % MOD; n >>= 1; } return ans;}long long f[1000001];void solve(){ long long 阅读全文
posted @ 2011-07-07 14:14 宇宙吾心 阅读(180) 评论(0) 推荐(0)
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