poj 1084
摘要:
原根的求法。代码:#include<iostream>#include<fstream>#include<cmath>using namespace std;int a[65537];int n;void read(){// ifstream cin("in.txt"); int i,j,k,ans,n; for(i=4;i<=65536;i+=2) a[i]=1; for(i=3;i<=65536;i+=2) if(a[i]==0) for(j=2*i;j<=65536;j+=2) a[j]=1; while(cin& 阅读全文
posted @ 2011-03-29 21:48 宇宙吾心 阅读(819) 评论(1) 推荐(1)
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